Question

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再次循环数组

foreach ($total_month_hours_result as $key => $data){ print_r($data); } //outputs below array

Array
(
    [0] => Array
        (
            [SITE_STATUS] => Offshore
            [ACTUAL_HOURS] => 176
            [MONTH_YEAR] => APR-2015
        )

    [1] => Array
        (
            [SITE_STATUS] => Onsite
            [ACTUAL_HOURS] => 180
            [MONTH_YEAR] => APR-2015
        )

)

尝试下面的代码

foreach ($data as $key => $val ){print_r($val);} // outputs below array


Array
(
    [SITE_STATUS] => Offshore
    [ACTUAL_HOURS] => 176
    [MONTH_YEAR] => APR-2015
)

Array
(
    [SITE_STATUS] => Onsite
    [ACTUAL_HOURS] => 180
    [MONTH_YEAR] => APR-2015
)

输出

$hours_array = Array();
foreach ($project_months as $month) {

    foreach ($total_month_hours_result as $key => $data){

        if (!empty($data)){

            foreach ($data as $key => $val ){

                if ($val['MONTH_YEAR'] == $month ){

                  $hours_array[$val['MONTH_YEAR']][$month]['SITE_STATUS'] = $val['SITE_STATUS'];
                  $hours_array[$val['MONTH_YEAR']][$month]['OFFSHORE_HOURS'] = $val['OFFSHORE_HOURS'];
                  $hours_array[$val['MONTH_YEAR']][$month]['ONSITE_HOURS'] = $val['ONSITE_HOURS'];
                  $hours_array[$val['MONTH_YEAR']][$month]['TOTAL_HOURS'] = $val['ONSITE_HOURS'] + $val['OFFSHORE_HOURS'];

                }
            }
        }
    }
}

基于键Array ( [APR-2015] => Array ( [APR-2015] => Array ( [SITE_STATUS] => Onsite [TOTAL_HOURS] => 356 [ONSITE_HOURS] => 180 [OFFSHORE_HOURS] => 176 ) ) )如何合并两个数组，得到以下输出

month_year

修改

我实际想要达到的目的是以表格形式显示现场，离岸和总时数，如下所示

它确实显示了第一个APR-2015的正确时间，但没有显示JUN-15

的时间

Array
(
    [SITE_STATUS] => Offshore
    [ACTUAL_HOURS] => 176
    [SITE_STATUS] => Onsite
    [ACTUAL_HOURS] => 180
    [MONTH_YEAR] => APR-2015
)

SQL：

Name of Engineer    Site  MAR-15  Site    APR-15  Site     JUN-15
User 1                            Onsite   120    Offshore  170              
User 2                            Offshore 140    Offshore  180

Total Hours                                260                                          350
Total Onsite                               120                                          0
Total Offshore                             140                                          350

SQL结果

SELECT  decode(pr.siteid,   397,   'Onsite',   398,   'Offshore') AS
site_status,
  SUM(tm.user_hours) AS
actual_hours,
  tm.month_year
FROM project_resource pr
INNER JOIN monthly_table tm ON tm.resource_id = pr.employeeid
 AND tm.project_id = pr.projectid
INNER JOIN resource_table rd ON rd.employeeid = pr.employeeid
INNER JOIN expband_view exbvw ON exbvw.employeeid = pr.employeeid
INNER JOIN mastercode_table mc ON mc.codeid = rd.primaryskill
WHERE tm.project_id = 741
 AND tm.month_year = 'APR-2015' --months will be passed dynamically
GROUP BY pr.siteid,tm.month_year
ORDER BY SITE_STATUS DESC

Answer 1

您的理想输出不是真的可以实现，但您可以使用它：

$results = array();

foreach ($total_month_hours_result as $rows) {
    foreach ($rows as $data) {
        $results[$data['MONTH_YEAR']][$data['SITE_STATUS']] = $data['ACTUAL_HOURS'];
    }
}

产生这个：

Array
(
    [APR-15] => Array
    (
        [Offshore] => 176,
        [Onsite]   => 180
    )
    // ...
)

PHP - 基于相同Key的循环和合并数组

1 个答案: