我有简单的spring-jpa配置,我配置了Hibernate' ImprovedNamingStrategy
。这意味着如果我的实体类有一个变量userName
,那么Hibernate应该将它转换为user_name
来查询数据库。但是在我升级到Hibernate 5之后,这个命名转换停止了工作。我收到了错误:
错误:未知栏' user0_.userName'在'字段列表'
这是我的Hibernate配置:
@Configuration
@EnableJpaRepositories("com.springJpa.repository")
@EnableTransactionManagement
public class DataConfig {
@Bean
public DataSource dataSource(){
DriverManagerDataSource ds = new DriverManagerDataSource();
ds.setDriverClassName("com.mysql.jdbc.Driver");
ds.setUrl("jdbc:mysql://localhost:3306/test");
ds.setUsername("root");
ds.setPassword("admin");
return ds;
}
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory(){
HibernateJpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
vendorAdapter.setShowSql(Boolean.TRUE);
vendorAdapter.setDatabase(Database.MYSQL);
LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
factory.setJpaVendorAdapter(vendorAdapter);
factory.setDataSource(dataSource());
factory.setPackagesToScan("com.springJpa.entity");
Properties jpaProperties = new Properties();
jpaProperties.put("hibernate.ejb.naming_strategy","org.hibernate.cfg.ImprovedNamingStrategy");
jpaProperties.put("hibernate.dialect","org.hibernate.dialect.MySQL5InnoDBDialect");
factory.setJpaProperties(jpaProperties);
factory.afterPropertiesSet();
return factory;
}
@Bean
public SharedEntityManagerBean entityManager() {
SharedEntityManagerBean entityManager = new SharedEntityManagerBean();
entityManager.setEntityManagerFactory(entityManagerFactory().getObject());
return entityManager;
}
@Bean
public PlatformTransactionManager transactionManager() {
JpaTransactionManager txManager = new JpaTransactionManager();
txManager.setEntityManagerFactory(entityManagerFactory().getObject());
return txManager;
}
@Bean
public ImprovedNamingStrategy namingStrategy(){
return new ImprovedNamingStrategy();
}
}
这是我的实体类:
@Getter
@Setter
@Entity
@Table(name="user")
public class User{
@Id
@GeneratedValue
private Long id;
private String userName;
private String email;
private String password;
private String role;
}
我不想在@Column注释中明确命名我的数据库字段。我希望我的配置可以隐式地将驼峰转换为下划线。
请指导。
答案 0 :(得分:58)
感谢您发布自己的解决方案。设置Hibernate 5命名策略对我有很大的帮助!
pre-Hibernate 5.0的hibernate.ejb.naming_strategy
属性似乎分为两部分:
hibernate.physical_naming_strategy
hibernate.implicit_naming_strategy
这些属性的值不像NamingStrategy
那样实现hibernate.ejb.naming_strategy
接口。为此目的有两个新接口:
org.hibernate.boot.model.naming.PhysicalNamingStrategy
org.hibernate.boot.model.naming.ImplicitNamingStrategy
Hibernate 5只提供PhysicalNamingStrategy
(PhysicalNamingStrategyStandardImpl
)的一个实现,它假定物理标识符名称与逻辑标识符相同。
ImplicitNamingStrategy
有几个实现,但我发现没有与旧ImprovedNamingStrategy
等效的实现。 (见:org.hibernate.boot.model.naming.ImplicitNamingStrategyLegacyHbmImpl
)
所以,我实现了自己的PhysicalNamingStrategy
,这非常简单:
public class PhysicalNamingStrategyImpl extends PhysicalNamingStrategyStandardImpl implements Serializable {
public static final PhysicalNamingStrategyImpl INSTANCE = new PhysicalNamingStrategyImpl();
@Override
public Identifier toPhysicalTableName(Identifier name, JdbcEnvironment context) {
return new Identifier(addUnderscores(name.getText()), name.isQuoted());
}
@Override
public Identifier toPhysicalColumnName(Identifier name, JdbcEnvironment context) {
return new Identifier(addUnderscores(name.getText()), name.isQuoted());
}
protected static String addUnderscores(String name) {
final StringBuilder buf = new StringBuilder( name.replace('.', '_') );
for (int i=1; i<buf.length()-1; i++) {
if (
Character.isLowerCase( buf.charAt(i-1) ) &&
Character.isUpperCase( buf.charAt(i) ) &&
Character.isLowerCase( buf.charAt(i+1) )
) {
buf.insert(i++, '_');
}
}
return buf.toString().toLowerCase(Locale.ROOT);
}
}
请注意,addUnderscores()
方法来自原始org.hibernate.cfg.ImprovedNamingStrategy
。
然后,我将此物理策略设置为persistence.xml文件:
<property name="hibernate.physical_naming_strategy" value="my.package.PhysicalNamingStrategyImpl" />
将Hibernate 5命名策略设置为以前的版本设置是一个陷阱。
答案 1 :(得分:3)
感谢SamuelAndrés提供的非常有用的答案,但是避免使用手写的蛇形逻辑可能是一个好主意。这是使用番石榴的相同解决方案。
它假设您的实体名称是用id ' productid ' stockin 'stockout 'VoucherType
-----------------------------------------
1 | 1 | 5 | 0 | 1
2 | 1 | 5 | 0 | 1
3 | 1 | 5 | 0 | 1
4 | 2 | 5 | 0 | 1
5 | 2 | 0 | 10 | 2
6 | 1 | 0 | 2 | 2
7 | 2 | 0 | 3 | 2
StandardJavaClassFormat
和列名称编写的
希望这可以节省一些人来这里使用谷歌搜索: - )
standardJavaFieldFormat
答案 2 :(得分:1)
希望这会有所帮助:
hibernate.implicit_naming_strategy = .... ImplicitNamingStrategy hibernate.physical_naming_strategy = .... PhysicalNamingStrategyImpl
这是代码(只是从现有代码中重新调整):
import java.io.Serializable;
import java.util.Locale;
import org.hibernate.boot.model.naming.Identifier;
import org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl;
import org.hibernate.engine.jdbc.env.spi.JdbcEnvironment;
public class PhysicalNamingStrategyImpl extends PhysicalNamingStrategyStandardImpl implements Serializable {
public static final PhysicalNamingStrategyImpl INSTANCE = new PhysicalNamingStrategyImpl();
@Override
public Identifier toPhysicalTableName(Identifier name, JdbcEnvironment context) {
return new Identifier(addUnderscores(name.getText()), name.isQuoted());
}
@Override
public Identifier toPhysicalColumnName(Identifier name, JdbcEnvironment context) {
return new Identifier(addUnderscores(name.getText()), name.isQuoted());
}
protected static String addUnderscores(String name) {
final StringBuilder buf = new StringBuilder( name.replace('.', '_') );
for (int i=1; i<buf.length()-1; i++) {
if (
Character.isLowerCase( buf.charAt(i-1) ) &&
Character.isUpperCase( buf.charAt(i) ) &&
Character.isLowerCase( buf.charAt(i+1) )
) {
buf.insert(i++, '_');
}
}
return buf.toString().toLowerCase(Locale.ROOT);
}
}
答案 3 :(得分:1)
感谢那篇文章。有点恼人,升级打破了表和列名称策略。而不是从ImprovedNamingStrategy
复制逻辑,您也可以使用委托。
public class TableNamingStrategy extends PhysicalNamingStrategyStandardImpl {
private static final String TABLE_PREFIX = "APP_";
private static final long serialVersionUID = 1L;
private static final ImprovedNamingStrategy STRATEGY_INSTANCE = new ImprovedNamingStrategy();
@Override
public Identifier toPhysicalTableName(Identifier name, JdbcEnvironment context) {
return new Identifier(classToTableName(name.getText()), name.isQuoted());
}
@Override
public Identifier toPhysicalColumnName(Identifier name, JdbcEnvironment context) {
return new Identifier(STRATEGY_INSTANCE.classToTableName(name.getText()), name.isQuoted());
}
private String classToTableName(String className) {
return STRATEGY_INSTANCE.classToTableName(TABLE_PREFIX + className);
}
}
答案 4 :(得分:1)
每个答案都通过实施PhysicalNamingStrategy
来发布解决方案,但是您需要(并且应该做的)就是实施ImplicitNamingStrategy
。
当实体未明确命名其映射到的数据库表时,我们需要隐式确定该表名。或者,当特定属性没有显式命名其映射到的数据库列时,我们需要隐式确定该列名称。在映射未提供显式名称的情况下,有一些org.hibernate.boot.model.naming.ImplicitNamingStrategy协定可用于确定逻辑名称的角色的例子。
代码可以像这样简单(与其他答案一样使用原始的addUnderscores
):
public class ImplicitNamingStrategyImpl extends ImplicitNamingStrategyJpaCompliantImpl {
@Override
protected Identifier toIdentifier(String stringForm, MetadataBuildingContext buildingContext) {
return super.toIdentifier(addUnderscores(stringForm), buildingContext);
}
protected static String addUnderscores(String name) {
final StringBuilder buf = new StringBuilder(name.replace('.', '_'));
for (int i = 1; i < buf.length() - 1; i++) {
if (Character.isLowerCase(buf.charAt(i - 1))
&& Character.isUpperCase(buf.charAt(i))
&& Character.isLowerCase(buf.charAt(i + 1))) {
buf.insert(i++, '_');
}
}
return buf.toString().toLowerCase(Locale.ROOT);
}
}
答案 5 :(得分:0)
没有Guava和Apache utils
public class PhysicalNamingStrategyImpl extends PhysicalNamingStrategyStandardImpl {
public Identifier toPhysicalTableName(Identifier name, JdbcEnvironment context) {
return context.getIdentifierHelper().toIdentifier(
name.getText().replaceAll("((?!^)[^_])([A-Z])", "$1_$2").toLowerCase(),
name.isQuoted()
);
}
public Identifier toPhysicalColumnName(Identifier name, JdbcEnvironment context) {
return context.getIdentifierHelper().toIdentifier(
name.getText().replaceAll("((?!^)[^_])([A-Z])", "$1_$2").toLowerCase(),
name.isQuoted()
);
}
}
答案 6 :(得分:-8)
刚刚发现问题,使用Hibernate版本时配置绝对正常&lt; 5.0但不适用于Hibernate&gt; = 5.0。
我在Spring 4.2.0.RELEASE中使用了Hibernate 5.0.0.Final。我猜Hibernate 5与Spring 4.2不完全兼容。我刚刚将Hibernate降级到4.2.1.Final,事情开始正常。
在Hibernate 5中不推荐使用Hibernate的<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
类。