我正在尝试通过ModelForm在CreateView中创建一个新对象。我想让'player'实例拥有一个图像。但上传的图像不会存储到'player_image'目录或写入数据库。
这些是我的文件:
models.py:
class Player(models.Model):
last_name = models.CharField(max_length=255, verbose_name=_("Last Name"))
first_name = models.CharField(max_length=255, verbose_name=_("First Name"))
secret_name = models.CharField(max_length=255, verbose_name=_("Secret Key"), unique=True)
image = ImageField(upload_to='player_images/', verbose_name=_("Image"), null=True, blank=True)
player_form.py
class PlayerForm(forms.ModelForm):
last_name = forms.CharField(required=True, label=_("Last Name"))
first_name = forms.CharField(required=True, label=_("First Name"))
class Meta:
model = Player
fields = ['first_name', 'last_name', 'image']
player_add_view.py
class PlayerAddView(LoginRequiredMixin, CreateView):
form_class = PlayerForm
template_name = "project/player_add_view.html"
model = Player
def form_valid(self, form):
player = form.save(commit=False)
# I do other stuff here
player.save()
return HttpResponseRedirect(reverse('home'))
答案 0 :(得分:9)
在views.py或enctype =" multipart / form-data"中可能会有一些缺失,如request.FILES。在表格中。
请看这里:https://docs.djangoproject.com/en/1.8/topics/http/file-uploads/
答案 1 :(得分:5)
转到您的模板并添加:
<form method="post" enctype="multipart/form-data">
答案 2 :(得分:0)
我不知道为什么它不能正常工作,但在我的项目中,哪个有效,我从后期请求中获取图像是这样的:
profile_form = ProfileForm(data=request.POST)
if profile_form.is_valid():
if 'picture' in request.FILES:
current_user.image = request.FILES['image']