Question

我有下表从我的数据库中查询用户，然后在每个用户下添加14个玩家。我在同一个数据库表中添加了几个列，我试图让列回显，并且它抛出一个未定义的索引错误，但我不完全确定在哪里可以定义它。

这是我试图让新列回应的部分。我有14个玩家，所以这个阵列为每个用户运行。我正在添加相同数量的＆＃39;职位＆＃39;所以它将是player1 position1，player2 position2等等。

for ($playerNum = 1; $playerNum <= $totalPlayerNumbers; $playerNum++) {
    echo '<tr><td><div class="draftBorder">' . $playerNum . '</div></td>';
    foreach ($userPlayerStore as $userPlayer) {
        echo '<td><div class="draftBorder">' . $userPlayer['player' . $playerNum] . '</div></td>';

我试图这样做，这就是我收到错误的原因......

 foreach ($userPlayerStore as $userPlayer) {
    echo '<td><div class="draftBorder">' . $userPlayer['player' . ' - ' . 'position' . $playerNum] . '</div></td>';

我还能如何格式化这个，以便我可以让位置显示在播放器旁边。像这样：

Player1 - Position1

完整代码：

<?php $userPlayerStore = array(); ?>

<table class="draft_border_table">
    <tr>
        <th>Rnd</th>

<?php

// Output usernames as column headings
$userResults = mysqli_query($con, 'SELECT * FROM user_players ORDER BY `id`');
while($userPlayer = mysqli_fetch_array($userResults)) {
    $userPlayerStore[] = $userPlayer;
    echo '<th><div>' . $userPlayer['username'] . '</div></th>';
}

?>

    </tr>

<?php

// Output each user's player 1-14 in each row
$totalPlayerNumbers = 14;
for ($playerNum = 1; $playerNum <= $totalPlayerNumbers; $playerNum++) {
echo '<tr><td><div class="draftBorder">' . $playerNum . '</div></td>';
foreach ($userPlayerStore as $userPlayer) {
     if (empty($userPlayer['player'.$playerNum])){
       $extra_class = 'emptycell';
    }else{
       $extra_class = 'filledcell';
    }
    echo '<td class="draft_table_td">' . $userPlayer['player' . $playerNum] . '</td>';
}
echo '</tr>';
}

?>

</table>

Answer 1

$ userPlayer var是数据库表中每条记录的反映，此数组中的每个索引都是列名。以下代码可以帮助您：

// Output each user's player 1-14 in each row
$totalPlayerNumbers = 14;
for ($playerNum = 1; $playerNum <= $totalPlayerNumbers; $playerNum++) {

    // Start the player row
    echo '<tr><td><div class="draftBorder">' . $playerNum . '</div></td>';

    foreach ($userPlayerStore as $userPlayer) {

        // Retrieve extra class name? Did you mean to use this?
        $extraClass = empty($userPlayer['player' . $playerNum]) ? 'emptycell' : 'filledcell';

        // Output player name and position
        $playerName = $userPlayer['player' . $playerNum];
        $playerPosition = $userPlayer['position' . $playerNum];
        echo '<td class="draft_table_td">' . $playerName . ' - ' . $playerPosition . '</td>';
    }

    // End the player row
    echo '</tr>';
}

向数组添加一组数据库列的问题

1 个答案: