Question

我在变量ArtTEXT中有这个（演示）文本。

1|Reporting Problems and Bugs. 
2|Other freely available awk implementations. 
5|Summary of installation. 
8|How to disable certain gawk extensions. 
3|Making Additions To gawk. 
7|Accessing the Git repository.

这是一个变量，其中的行用已知的字符串分隔。

我想将它拆分为一个数组，其中行开头的数字将是使用一个命令的数组行的索引，而不是循环遍历行。

结果应为：

arr[1] => Reporting Problems and Bugs. 
arr[2] => Other freely available awk implementations. 
arr[5] => Summary of installation. 
arr[8] => How to disable certain gawk extensions. 
arr[3] => Making Additions To gawk. 
arr[7] => Accessing the Git repository.

这可能吗？

Answer 1

不，这是不可能的。以下是如何根据需要从变量填充数组（假设分隔行的“已知字符串”是换行符）：

$ awk -v ArtTEXT='1|Reporting Problems and Bugs.
2|Other freely available awk implementations.
5|Summary of installation.
8|How to disable certain gawk extensions.
3|Making Additions To gawk.
7|Accessing the Git repository.' '
BEGIN {
    split(ArtTEXT,lines,/\n/)
    for (lineNr in lines) {
        split(lines[lineNr],flds,/\|/)
        arr[flds[1]] = flds[2]
    }

    for (i in arr) {
        printf "arr[%d] => %s\n", i, arr[i]
    }
}
'
arr[1] => Reporting Problems and Bugs.
arr[2] => Other freely available awk implementations.
arr[3] => Making Additions To gawk.
arr[5] => Summary of installation.
arr[7] => Accessing the Git repository.
arr[8] => How to disable certain gawk extensions.

Answer 2

不需要使用数组，因为您只需更改字段分隔符。

awk 'BEGIN{FS="|"}{print $1, $2}' input.txt

$ 0包含整行 $ 1包含索引判罚2美元

Answer 3

如果记录分隔符是换行符，则可以使用引号扩展回显变量并像往常一样使用awk，例如

echo "$ArtTEXT" | awk -F"|" '{ix[NR]=$1;arr[$1]=$2} END{for(i=1;i<=NR;i++) print "arr[" ix[i] "] => " arr[ix[i]]}' 

arr[1] => Reporting Problems and Bugs. 
arr[2] => Other freely available awk implementations. 
arr[5] => Summary of installation. 
arr[8] => How to disable certain gawk extensions. 
arr[3] => Making Additions To gawk. 
arr[7] => Accessing the Git repository.

由于awk数组不保留顺序，因此需要为其保留单独的索引。

AWK - 使用索引将变量拆分为数组而不进行循环

3 个答案: