我需要读取文件的某些部分并将它们放入正确的数组中。
public static void load(String fileName, String[] itemNumbers,
String[] itemNames, double[] priceOfItem, int[] quantity) throws IOException{
int i = 0;
File inFile = new File(fileName);
Scanner reader = new Scanner(inFile);
while(reader.hasNext()){
itemNumbers[i] = reader.next();
itemNames[i] = reader.next();
priceOfItem[i] = reader.nextDouble();
quantity[i] = reader.nextInt();
i++;
}
//This is just to see if it worked
System.out.println(itemNumbers[i]);
System.out.println(itemNames[i]);
System.out.println(priceOfItem[i]);
System.out.println(quantity[i]);
}
以下是我正在阅读的文件。
E3233 CordlessDrill 129.99 12
W2321 WindowSealer 3.39 84
数组与文件部分按顺序排列。 当我运行这个时,我收到以下
null
null
0.0
0
答案 0 :(得分:0)
确保说明 而(reader.hasNextLine())
答案 1 :(得分:0)
你尝试过使用FileReader吗?
public static void load(String fileName, String[] itemNumbers,
String[] itemNames, double[] priceOfItem, int[] quantity) throws IOException{
File inFile = new File(fileName);
char[] cbuf = new char[(int) inFile.length()];
FileReader r = new FileReader(inFile);
r.read(cbuf);
String finalString = String.valueOf(cbuf);
String[] lines = finalString.split("\n");
itemNumbers = new String[lines.length];
itemNames = new String[lines.length];
priceOfItem = new double[lines.length];
quantity = new int[lines.length];
for(int i = 0; i < lines.length; i++){
String line = lines[i].replace("\n", "");
String[] values = line.split(" ");
String itemNumber = values[0];
String itemName = values[1];
double price = Double.parseDouble(values[2]);
int quant = Integer.parseInt(values[3].replace(String.valueOf((char)13), "").replace(" ", "").replace("\"", ""));
itemNumbers[i] = itemNumber;
itemNames[i] = itemName;
priceOfItem[i] = price;
quantity[i] = quant;
}
r.close();
for(int i = 0; i < itemNames.length; i++){
System.out.println(itemNumbers[i]);
System.out.println(itemNames[i]);
System.out.println(priceOfItem[i]);
System.out.println(quantity[i]);
System.out.println("\n");
}
}
这个方法依赖于在文件中使用空格,为了安全起见,我会用逗号添加逗号和结束行,但是如果你保持相同的格式,这应该有效。