Question

我有这样的查询

"SELECT booking.referance_no AS ref_no,
        booking.entry_date AS dep_date,
        TIME_FORMAT(booking.entry_time,'%H:%i') as dep_time,
        booking.first_name AS fname,
        booking.last_name AS lname,
        booking.mobile AS mobile
    FROM booking WHERE $WHERE1
    GROUP BY booking.book_id
    UNION ALL
SELECT supplier.reference_no AS ref_no,
        DATE_FORMAT(supplier.departure_date_time,'%d-%m-%Y') AS dep_date,
        TIME_FORMAT(supplier.departure_date_time,'%H:%i') AS dep_time,
        supplier.fname AS fname,
        supplier.lname AS lname,
        supplier_subscribers.mobile AS mobile
    FROM supplier WHERE $WHERE2 
    ORDER BY `dep_date` ASC, `dep_time` ASC";

和Where子句

$WHERE1="STR_TO_DATE(booking.entry_date, '%d-%M-%Y') BETWEEN '".$from_date." 00:00:00' AND '".$to_date." 23:59:59'";
$WHERE2="supplier.departure_date_time BETWEEN '".$from_date." 00:00:00' AND '".$to_date." 23:59:59'";

情景一

在24小时内搜索ORDER BY dep_date ASC, dep_time ASC我会得到这样的结果

在上面的快照中检查行63和64，结果按date排序，但不是time排序，第一个结果显示从supplier表到行63然后从表64开始booking，结果按照每个表（第一个supplier表格然后booking排序表），然后按date和time排序。

如果在24小时内仅使用ORDER BY dep_time ASC进行搜索，我会按时间正确排序。

情景二

如果在48小时或更长时间内仅使用ORDER BY dep_time ASC进行搜索，我会得到以下结果

未按日期排序当然它仅按time排序，因此无用。

如果使用ORDER BY dep_date ASC, dep_time ASC在48小时或更长时间内进行搜索，我会得到与第一个快照相同的结果;

第一个结果按表supplier然后booking排序，但前24小时然后是24小时
然后，每24小时内，每个表格结果将分别按date和time排序。

那么，无论日期范围是什么，我如何根据date和time对两个表的结果进行排序？

Answer 1

使用Concat

ORDER BY concat(dep_date,' ',dep_time)` ASC

尝试以下查询，希望这可行

select * from (SELECT booking.referance_no AS ref_no,
        booking.entry_date AS dep_date,
        TIME_FORMAT(booking.entry_time,'%H:%i') as dep_time,
        booking.first_name AS fname,
        booking.last_name AS lname,
        booking.mobile AS mobile
    FROM booking WHERE $WHERE1
    GROUP BY booking.book_id
    UNION ALL
SELECT supplier.reference_no AS ref_no,
        DATE_FORMAT(supplier.departure_date_time,'%d-%m-%Y') AS dep_date,
        TIME_FORMAT(supplier.departure_date_time,'%H:%i') AS dep_time,
        supplier.fname AS fname,
        supplier.lname AS lname,
        supplier_subscribers.mobile AS mobile
    FROM supplier WHERE $WHERE2 ) as temp ORDER BY concat(dep_date,' ',dep_time)` ASC

Answer 2

~~您可以order by supplier.departure_date_time，因为这已经是正确的顺序。~~

好的，抱歉。我刚刚阅读了有关UNION语法的MySQL Reference Manual。

要使用ORDER BY或LIMIT子句对整个UNION结果进行排序或限制，请为各个SELECT语句加上括号，并将ORDER BY或LIMIT置于最后一个之后。

"
(
SELECT 
  booking.referance_no AS ref_no,
  booking.entry_date AS dep_date,
  TIME_FORMAT(booking.entry_time,'%H:%i') as dep_time,
  booking.first_name AS fname,
  booking.last_name AS lname,
  booking.mobile AS mobile
FROM booking 
WHERE $WHERE1
GROUP BY booking.book_id
)
UNION ALL
(
SELECT 
  supplier.reference_no AS ref_no,
  DATE_FORMAT(supplier.departure_date_time,'%d-%m-%Y') AS dep_date,
  TIME_FORMAT(supplier.departure_date_time,'%H:%i') AS dep_time,
  supplier.fname AS fname,
  supplier.lname AS lname,
  supplier_subscribers.mobile AS mobile
FROM supplier 
WHERE $WHERE2
) 
ORDER BY `dep_date` ASC, `dep_time` ASC
";

MySQL结果ORDER BY日期和时间

2 个答案: