我有2个日期 - 开始和结束。我想验证(并重新确保)开始<结束。 我收到通知,他们使用$ watch进行更改,然后我去更改它们以确保满足条件,但是它再次触发$ watch然后我获得$ digest的最大迭代次数并且事情向南移动。
所以我的问题是 - 如何更改在$watch
内观察的变量而不会导致无限循环。 (除了有更多检查并且只有在实际需要更改时才更改它们)
这是我的代码:
var TIME_DAY = 1000 * 60 * 60 * 24;
$scope.$watch('timeFilter.startTime', function () {
validateStartEndTime();
},true);
$scope.$watch('timeFilter.endTime', function () {
validateStartEndTime();
},true);
function validateStartEndTime() {
if ($scope.timeFilter.startTime != null && $scope.timeFilter.endTime != null) {
// Remove all seconds
if ($scope.timeFilter.startTime.getSeconds() > 0)
$scope.timeFilter.startTime.setSeconds(0);
if ($scope.timeFilter.endTime.getSeconds() > 0)
$scope.timeFilter.endTime.setSeconds(0);
if ($scope.timeRange.minTime.getSeconds() > 0)
$scope.timeRange.minTime.setSeconds(0);
if ($scope.timeRange.maxTime.getSeconds() > 0)
$scope.timeRange.maxTime.setSeconds(0);
// When start time isn't before end time
if ($scope.timeFilter.startTime >= $scope.timeFilter.endTime) {
// We want to increase end time by 1 minute, if possible - do it. Else - reduce start time by 1 minute
if ($scope.timeFilter.endTime < $scope.timeRange.maxTime) {
$scope.timeFilter.endTime.setMinutes($scope.timeFilter.startTime.getMinutes() + 1);
} else {
$scope.timeFilter.startTime.setMinutes($scope.timeFilter.startTime.getMinutes() - 1);
}
}
// Start time before min time
if ($scope.timeFilter.startTime < $scope.timeRange.minTime) {
$scope.timeFilter.startTime = $scope.timeRange.minTime;
if ($scope.timeFilter.endTime <= $scope.timeFilter.startTime) {
$scope.timeFilter.endTime = $scope.timeFilter.startTime;
$scope.timeFilter.endTime.setMinutes($scope.timeFilter.endTime.getMinutes() + 1);
}
}
// End time after max time
if ($scope.timeFilter.endTime > $scope.timeRange.maxTime) {
$scope.timeFilter.endTime = $scope.timeRange.maxTime;
if ($scope.timeFilter.startTime >= $scope.timeFilter.endTime) {
$scope.timeFilter.startTime = $scope.timeFilter.endTime;
$scope.timeFilter.startTime.setMinutes($scope.timeFilter.startTime.getMinutes() - 1);
}
}
}
}
答案 0 :(得分:1)
老实说,我宁愿找到一种方法来避免改变经常观看的变量。但是,如果你真的想要,你可以在必须更改被监视的变量时取消注册你的$ watch函数,然后重新注册$ watch函数。
要取消注册$ watch函数,您只需要获取引用并在需要时调用。
var myWatch = $scope.$watch('timeFilter.startTime', function () {
validateStartEndTime();
},true);
myWatch(); // It will deregister it.
请记住,有时当您第一次观看变量时,它会自动触发该功能。我的建议是总是检查旧变量是否真的改变了。
var myWatch = $scope.$watch('timeFilter.startTime', function (newValue, oldValue) {
if(newValue === oldValue){
return;
}
validateStartEndTime();
},true);
我希望它适合你。不幸的是,我现在无法测试此代码。
答案 1 :(得分:0)
我结合了回复这样的人的建议和建议:
$scope.$watch('timeFilter.startTime', function(newValue, oldValue) {
if (newValue === oldValue) return;
validateStartEndTime();
}, true);
$scope.$watch('timeFilter.endTime', function(newValue, oldValue) {
if (newValue === oldValue) return;
validateStartEndTime();
}, true);
function validateStartEndTime(startChanged) {
if ($scope.timeFilter.startTime == null || $scope.timeFilter.endTime == null) return;
var tempStart = new Date($scope.timeFilter.startTime), tempEnd = new Date($scope.timeFilter.endTime);
if ($scope.timeRange.minTime && $scope.timeRange.maxTime) {
// Logic start
// Logic ends
if ($scope.timeFilter.startTime !== tempStart)
$scope.timeFilter.startTime = tempStart;
if ($scope.timeFilter.endTime !== tempEnd)
$scope.timeFilter.endTime = tempEnd;
}
}
这样我确保尽可能少做一些更改。如果有人有任何建议,我愿意接受建议