Question

我有一个MySQL数据库，其中有我要加载到Listview的图像的blob。

我正在尝试使用毕加索。但问题是 - 如何执行POST请求，通过（$ _POST in PHP）发送参数 - 将其转换为url，最后库将其加载到imageview中？哪个是最佳选择？

我目前获取图像的实现如下：

 public View getView(final int position, View convertView, ViewGroup parent) {

    // TODO Auto-generated method stub
    ----------------------------
    ----------------------------



    if (!"N".equalsIgnoreCase(listOfPosts.get(position).getHasImage()) ) {
        if(mMemoryCache.get(postId)== null )
            new GetPrimaryImages(position, holder).execute(image);
        else
             holder.ivPrimaryImage.setImageBitmap(mMemoryCache.get(postId));
    }else {
        holder.ivPrimaryImage.setImageResource(R.drawable.search);
    }

    return rowView;
}

GetPrimaryImages类的位置如下：

  public class GetPrimaryImages extends AsyncTask<Image, Void, Bitmap> {


    int mPosition;
    Holder mHolder;
    public GetPrimaryImages(int position, Holder holder){
        mPosition = position;
        mHolder = holder;
    }


    ImageView imageView = null;
    protected Bitmap doInBackground(Image... images) {
    this.imageView=images[0].getImg();



        // Building Parameters
        List<NameValuePair> params = new ArrayList<NameValuePair>();
        params.add(new BasicNameValuePair("postid",(String)(this.imageView.getTag()) ));

        JSONObject json;

        if(mHolder.position == mPosition)
             json = jsonParser.makeHttpRequest(CommonResources.getURL("get_primary_image"),
                    "POST", params);

        else {
            json = null;
            cancel(true);
        }


        if(json == null){
            //latch.countDown();
            return null;
        }
        Log.d("Fetching Image",imageView.getTag()+ json.toString());

        // check for success tag
        String TAG_SUCCESS = "success";
        try {
            int success = json.getInt(TAG_SUCCESS);

            if (success == 0) {
               image =  json.getString("primaryimage");

            }
        } catch (JSONException e) {
            e.printStackTrace();
        }

        return getImage(image);

    }


    protected void onPostExecute(Bitmap result) {
        if (mHolder.position == mPosition) {
            mMemoryCache.put((String) imageView.getTag(), result);

            imageView.setImageBitmap(result);
        }

    }






}

Answer 1

Tty this

Picasso.with（上下文）.load（URL）.placeholder（R.drawable.no_image）.into（ImageView的）;

如何使用Picasso从远程PHP-MySQL blob加载图像？

1 个答案: