计数显示为未定义

Question

我正在尝试在循环中添加count函数，以便显示的用户将获得一个订单号。像这样......

1. 用户1
2. 用户2
3. 用户3 等

截至目前，计数编号显示为未定义。

$count = 0;
foreach ($array as $result) :
$count++;
$shuffle_count = $count;
    $shuffle_firstname = htmlentities($result['firstname']);
    $shuffle_lastname = htmlentities($result['lastname']);
    $shuffle_id = htmlentities($result['id']);
    $shuffle_username = htmlentities($result['username']);
    $shuffle_email = htmlentities($result['email']);
?>
    <input type="hidden" name="count[]" value="<?php echo $shuffle_count; ?>">
        <input type="hidden" name="firstname[]" value="<?php echo $shuffle_firstname; ?>">
        <input type="hidden" name="lastname[]" value="<?php echo $shuffle_lastname; ?>">
        <input type="hidden" name="id[]" value="<?php echo $shuffle_id; ?>">
    <input type="hidden" name="username[]" value="<?php echo $shuffle_username; ?>">
    <input type="hidden" name="email[]" value="<?php echo $shuffle_email; ?
    >">

    <?php 

        endforeach;

的Javascript

var displayResults = function(data){
                var i = 0;
                var lineheight = 24;
                var time = 3000;
                var interval = setInterval(function(){ 
                    if( i <= data.length){ 
                        console.log( data[i] ); 
                        $('#results').append('<div class="result">' +
                                    //'<div class="shuffle_results">' + data[i].firstname + ' ' + data[i].lastname + '</div>' + 
                                    '<div class="shuffle_results">' + data[i].drafted_order + ' '+ data[i].firstname + ' ' + data[i].lastname + '</div>' + 
                                    '<input type="hidden" name="count[]" value="' + data[i].drafted_order + '">' +
                                    '<input type="hidden" name="firstname[]" value="' + data[i].firstname + '">' +
                                    '<input type="hidden" name="lastname[]" value="' + data[i].lastname + '">' +
                                    '<input type="hidden" name="id[]" value="' + data[i].id + '">' +
                                    '<input type="hidden" name="username[]" value="' + data[i].username + '">' +
                                    '<input type="hidden" name="email[]" value="' + data[i].email + '">' +
                                '</div>');
                       var $this = $('.shuffle_results:last'); 
                        $this.show().animate({ 
                            'left': 0 + 'px', 
                            'bottom': + '0px' 
                            //$(document).height() - (lineheight * data.length)
                        }, { 
                            duration: time 
                        });
                    i++;
                    } else { 
                        clearInterval(interval); 
                    } 
                }, 3000); 
            };

我收到此错误..

Uncaught TypeError: Cannot read property 'drafted_order' of undefined.

我试图改变这两行......

'<div class="shuffle_results">' + data[i].drafted_order + ' '+ data[i].firstname + ' ' + data[i].lastname + '</div>' + 
    '<input type="hidden" name="count[]" value="' + data[i].drafted_order + '">' +

对此：

'<div class="shuffle_results">' + data[i].count + ' '+ data[i].firstname + ' ' + data[i].lastname + '</div>' + 
    '<input type="hidden" name="count[]" value="' + data[i].count + '">' +

但是，它没有解决问题，填充了相同的错误。如果要显示这个数据，我做错了什么？

更新：已添加。

$(function(){  
                $('form[name="form"]').on('submit', function(e){
                    e.preventDefault();
                   $.post('shuffle_results.php', function(data){ 
                    var o = $.parseJSON(data); 
                    displayResults(o); 
                    });
                    });
                });

PHP for displayresults（o）

$query = mysqli_query($con, "SELECT * FROM users WHERE `group` = 3");
$array = array();

while ($row = mysqli_fetch_assoc($query)) { 
$array[] = array( 
'id' => $row['id'],
'firstname' => $row['firstname'], 
'lastname' => $row['lastname'], 
'username' => $row['username'], 
'email' => $row['email'] 
); 

if (isset($_POST['shuffle'])) {

    }
}
shuffle($array);
    echo json_encode($array);