Question

我正在使用Sonata Admin bundle作为我网站的后端。

我的数据库中的用户表如下所示：

id (PK)
username
email
password
salt
last_login
created_at
company_id (FK)

我的用户实体如下所示：

<?php

namespace MyBundle\Entity;

use FOS\UserBundle\Entity\User as BaseUser;
//use Sonata\UserBundle\Entity\BaseUser as BaseUser;
use Doctrine\ORM\Mapping as ORM;

/**
 * User
 *
 * @ORM\Table(name="user", indexes={@ORM\Index(name="fk_user_company1_idx", columns={"company_id"})})
 * @ORM\Entity
 */
class User extends BaseUser
{
    /**
     * @var \DateTime
     *
     * @ORM\Column(name="created_at", type="datetime", nullable=true)
     */
    protected $createdAt;

    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="IDENTITY")
     */
    protected $id;

    /**
     * @var \MyBundle\Entity\Company
     *
     * @ORM\ManyToOne(targetEntity="MyBundle\Entity\Company")
     * @ORM\JoinColumns({
     *   @ORM\JoinColumn(name="company_id", referencedColumnName="id")
     * })
     */
    protected $company;

    public function __construct()
    {
        parent::__construct();
        // your own logic
    }

    /**
     * Set username
     *
     * @param string $username
     * @return User
     */
    public function setUsername($username)
    {
        $this->username = $username;

        return $this;
    }

    /**
     * Get username
     *
     * @return string 
     */
    public function getUsername()
    {
        return $this->username;
    }

    /**
     * Set email
     *
     * @param string $email
     * @return User
     */
    public function setEmail($email)
    {
        $this->email = $email;

        return $this;
    }

    /**
     * Get email
     *
     * @return string 
     */
    public function getEmail()
    {
        return $this->email;
    }

    /**
     * Set password
     *
     * @param string $password
     * @return User
     */
    public function setPassword($password)
    {
        $this->password = $password;

        return $this;
    }

    /**
     * Get password
     *
     * @return string 
     */
    public function getPassword()
    {
        return $this->password;
    }

    /**
     * Set salt
     *
     * @param string $salt
     * @return User
     */
    public function setSalt($salt)
    {
        $this->salt = $salt;

        return $this;
    }

    /**
     * Get salt
     *
     * @return string 
     */
    public function getSalt()
    {
        return $this->salt;
    }

    /**
     * Get id
     *
     * @return integer 
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * Set company
     *
     * @param \MyBundle\Entity\Company $company
     * @return User
     */
    public function setCompany(\MyBundle\Entity\Company $company = null)
    {
        $this->company = $company;

        return $this;
    }

    /**
     * Get company
     *
     * @return \MyBundle\Entity\Company 
     */
    public function getCompany()
    {
        return $this->company;
    }
}

现在，当我转到“编辑帐户”页面时，我收到以下错误：

Warning: call_user_func() expects parameter 1 to be a valid callback, class 'MyBundle\Entity\User' does not have a method 'getGenderList'

我的数据库中的用户表中没有性别。我该如何解决这个问题？

更新

当我将use FOS\UserBundle\Entity\User as BaseUser;更改为use Sonata\UserBundle\Entity\BaseUser as BaseUser;时。然后我收到以下错误：

执行'SELECT t0.username AS username1，t0.username_canonical AS username_canonical2，t0.email AS email3，t0.email_canonical AS email_canonical4，t0.enabled AS enabled5，t0.salt AS salt6，t0.password AS时发生异常password7，t0.last_login AS last_login8，t0.locked AS locked9，t0.expired AS expired10，t0.expires_at AS expires_at11，t0.confirmation_token AS confirmation_token12，t0.password_requested_at AS password_requested_at13，t0.roles AS roles14，t0.credentials_expired AS credentials_expired15， t0.credentials_expire_at AS credentials_expire_at16，t0.created_at AS created_at17，t0.updated_at AS updated_at18，t0.date_of_birth AS date_of_birth19，t0.firstname AS firstname20，t0.lastname AS lastname21，t0.website AS website22，t0.biography AS tradition23，t0。性别AS gender24，t0.locale AS locale25，t0.timezone AS timezone26，t0.phone AS phone27，t0.facebook_uid AS facebook_uid28，t0.facebook_name AS facebook_name29，t0.facebook_data AS facebook_data30，t0.twitt er_uid AS twitter_uid31，t0.twitter_name AS twitter_name32，t0.twitter_data AS twitter_data33，t0.gplus_uid AS gplus_uid34，t0.gplus_name AS gplus_name35，t0.gplus_data AS gplus_data36，t0.token AS token37，t0.two_step_code AS two_step_code38，t0.id AS id39，t0.company_id AS company_id40 FROM user t0 WHERE t0.id =？限制1'与params 1：

SQLSTATE [42S22]：找不到列：1054未知列't0.updated_at'   在'字段列表'

我该如何解决这个问题？

Answer 1

您的User类扩展了FOSUserBundle而不是SonataUserBundle。你必须改变它：

//use FOS\UserBundle\Entity\User as BaseUser;
use Sonata\UserBundle\Entity\BaseUser as BaseUser;

检查https://github.com/sonata-project/SonataUserBundle/issues/459

编辑：如果你不想使用这个类（其中有很多无用的字段），那么你必须为你的用户实体创建自己的管理类。此页面提供了完整的指南：http://m2mdas.github.io/blog/2013/11/18/integrate-fosuserbundle-and-sonatauserbundle-easily/

更新后更新： 在更改实体扩展的类之后，您必须更新数据库模式以匹配您的模型：

php app/console doctrine:schema:update --force

类'... \ Entity \ User'没有方法'getGenderList'

1 个答案: