Question

有人可以帮助以下查询。下面提到的代码不返回FirstName和LastName。为什么呢？

干杯， Akhil G

<?php 

        $username = mysql_real_escape_string($_GET['user']);
        $firstname ="" ;
        $lastname ="";
            if (ctype_alnum($username))
            {
                //check user exist

                $check = mysql_query("SELECT username, first_name, last_name FROM syn where username = '$username'");
                if (mysql_num_rows($check) === 1)
                {
                    $get = mysql_fetch_array($check);
                    $username = $get['username'];
                    $firstname = $get['first_name'];
                    $lastname = $get['last_name'];
                } else 
                echo "<h2> User Does Not Exist ! </h2>";
                exit();
            }   
?>

Answer 1

您使用了错误的获取功能

$get = mysql_fetch_array($check);

将数据存储在数组中的编号位置，因此返回的数据存储在$ get [0]，$ get [1]和$ get [2]中。

您可以使用print_r（$ get）;

查看内容

改为使用

$get = mysql_fetch_assoc($check);

将数据存储在您需要的关联数组中。

Answer 2

试试这个..

<?php 

        $username = mysql_real_escape_string($_GET['user']);
        $firstname ="" ;
        $lastname ="";
            if (ctype_alnum($username))
            {
                //check user exist

                $check = mysql_query("SELECT username, first_name, last_name FROM syn where username = '$username'");
                if (!$check)
                {
                    $get = mysql_fetch_row($check);
                    $username = $get[0];
                    $firstname = $get[1];
                    $lastname = $get[2];
                } else 
                    echo "<h2> User Does Not Exist ! </h2>";
                exit();
            }   
?>

Answer 3

谢谢大家..但似乎我运气不好..似乎没有工作..尝试了所有选项建议..下面是修改后的版本，再次没有打印名字姓氏或用户名

<?php
include("./inc/header.inc.php");
?>

<?php

if (isset($_GET['user']))
  {
    $username = mysql_real_escape_string($_GET['user']);
    $firstname ="" ;
    $lastname ="";
        if (ctype_alnum($username))
        {
            //check user exist
            $check = mysql_query("SELECT username, first_name, last_name FROM syn where username = '$username'");
            if (mysql_num_rows($check) === 1)
            {
                $get = mysql_fetch_assoc($check);
                $username = $get['username'];
                $firstname = $get['first_name'];
                $lastname = $get['last_name'];
            } else 
            echo "<meta http-equiv =\"refresh\" content=\"0; url = http://localhost:8080/FirstTry/Tests/index.php\">";
            exit();
        }
}   
?>

<div class="postForm" > Post form will go in here .. </div>
<div class="postPosts" > Your Post will go in here ..</div>
<img src ="" height="250" width="200" alt ="<?php echo $firstname; ?>'s profile" title="<? echo $firstname; ?>'s profile"/>

mysql_fetch_array没有返回任何内容

3 个答案: