我有以下对象,需要这个字符串:
product_name,@dummy1,@dummy2,seller_sku,@price,item_quantity,@dummy6,@dummy7,@dummy8,@dummy9,@dummy10,@dummy11,@dummy12,@dummy13,@dummy14,@dummy15,@dummy16,@dummy17,@dummy18,@dummy19,@dummy20,@dummy21,@dummy22,@dummy23,@dummy24,@dummy25,fulfillment_channel
{
countFields: 27,
fields:
{ product_name: 0,
seller_sku: 3,
price: 4,
item_quantity: 5,
fulfillment_channel: 26
}
}
对象和字符串(包括长度)可能会发生变化。
我像这样创建字符串(使用lodash):
function tableString(fields){
var obj = _.invert(fields.fields);
obj.length = fields.countFields;
var values = Array.prototype.slice.apply( obj );
var arr = _.merge(new Array(fields.countFields),values).map(function(val,i){
if (val == 'price' || !~values.indexOf(val)) {
if (val == 'price') {
return '@price';
}
return '@dummy' + i;
}
return val;
});
return arr.join(',');
}
var first = {
countFields: 27,
fields: {
product_name: 0,
seller_sku: 3,
price: 4,
item_quantity: 5,
fulfillment_channel: 26
}
}
console.log(tableString(first));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/3.10.1/lodash.min.js"></script>
&#13;
我想避免最后的map()
/数组函数。有人找到一种更简单的方法从对象创建上面的字符串吗?
答案 0 :(得分:3)
我不知道这是否更容易,但你最后得到一个字符串及其香草javascript。
function tableString(fields){
var reversedFields = {};
for(var key in fields.fields){ // we swapped key and value
reversedFields[fields.fields[key]] = key;
}
for(var i=0,x=fields.countFields-1,result = "";i<fields.countFields;i++){
if(reversedFields[i]){
result += (reversedFields[i] == 'price' ? '@price' : reversedFields[i]);
} else {
result += '@dummy' + i;
}
if(i < x){
result += ",";
}
}
return result;
}
var res = tableString({
countFields: 27,
fields:{
product_name: 0,
seller_sku: 3,
price: 4,
item_quantity: 5,
fulfillment_channel: 26
}
});
// result product_name,@dummy1,@dummy2,seller_sku,@price,item_quantity,@dummy6,@dummy7,@dummy8,@dummy9,@dummy10,@dummy11,@dummy12,@dummy13,@dummy14,@dummy15,@dummy16,@dummy17,@dummy18,@dummy19,@dummy20,@dummy21,@dummy22,@dummy23,@dummy24,@dummy25,fulfillment_channel