我整个上午一直在努力和奋斗让我的组合框正确更新。一旦用户在第一个框中选择并选择我想要填充第二个框,其中包含适用于所选第一个选项的选项。我已经编写了一个单独的php脚本来接受所选的选项,并从sql数据库中提取适用的返回值。这个脚本在单独运行时工作正常,但我无法使用AJAX在javascript中工作
PHP:
<?php
$name=$_GET['name'];
// select box option tag
$selectBoxOption1 = '';
// connect mysql server
$con=mysql_connect('localhost', 'root', '');
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('mysql',$con);
$sql1 = "SELECT DISTINCT bike_type FROM bc_fit WHERE name='$name'";
$result1 = mysql_query($sql1);
// play with return result array
while($row = mysql_fetch_array($result1)){
$selectBoxOption1 .="<option value = '".$row['bike_type']."'>".$row['bike_type']."</option>";
}
// return options
echo $selectBoxOption1;
?>
Javascript(#nap2是当前框,#nap 4是下一个):
$("#nap2").change(function(event){
var selected = $(this).find('option:selected').text()
$('#nap4').removeAttr('disabled');
$('#nap4').empty();
//need to get options based upon nap 2 choice by calling php script with selected and returning all unqiue bike under that name
var options4;
$.ajax({
type: "GET",
url: 'getbiketype.php',
data: "name"=selected,
success: function(data) {
options4 = data;
}
});
$('#nap4').append($(options4));
});
答案 0 :(得分:1)
你的jQuery中有一些问题:
<select id="nap2" class="napkeeComponent napkeeCombobox">
<option value="1">One</option>
<option value="2">Two</option>
<option value="2">Three</option>
</select>
<select id="nap4" class="napkeeComponent napkeeCombobox" disabled>
</select>
<script>
$(document).ready(function() {
$("#nap2").change(function(event){
// You just get the value of selected input
// You don't need to find anything because you've already selected it
var selected = $(this).val();
$('#nap4').removeAttr('disabled');
$('#nap4').empty();
$.ajax({
type: "GET",
url: 'getbiketype.php',
// Your creation of the data object is incorrect
data: { name: selected },
success: function(data) {
console.log(data);
// Here just append the straight data
$('#nap4').append(data);
}
});
});
});
</script>