Question

我有桌子：

* ruletbl

| id_rule | code_rule |
-----------------------
|    1    |   R01     |
|    2    |   R01     |
|    3    |   R01     |
|    4    |   R02     |
|    5    |   R02     |
|    6    |   R02     |
-----------------------

和第二张表* detailRuletbl：

|  id_detailRule   | id_rule |  id_sym  |  codeDetailrule | orderNO |
---------------------------------------------------------------------
|        1         |    1    |     1    |     R01#1       |    1   |
|        2         |    1    |     2    |     R01#1       |    1   |
|        3         |    1    |     3    |     R01#1       |    1   |
|        4         |    2    |     4    |     R01#2       |    2   |
|        5         |    2    |     1    |     R01#2       |    2   |
|        6         |    2    |     2    |     R01#2       |    2   |
|        7         |    3    |     4    |     R01#3       |    3   |
|        8         |    3    |     3    |     R01#3       |    3   |
|        9         |    3    |     1    |     R01#3       |    3   |
|        10        |    4    |     6    |     R02#1       |    1   |
|        11        |    4    |     7    |     R02#1       |    1   |
|        12        |    4    |     5    |     R02#1       |    1   |
|        13        |    5    |     4    |     R02#2       |    2   |
|        14        |    5    |     1    |     R02#2       |    2   |
|        15        |    5    |     2    |     R02#2       |    2   |
|        16        |    5    |     8    |     R02#2       |    2   |
|        17        |    6    |     6    |     R02#3       |    3   |
|        18        |    6    |     8    |     R02#3       |    3   |
|        19        |    6    |     2    |     R02#3       |    3   |
|        20        |    6    |     1    |     R02#3       |    3   |
--------------------------------------------------------------------

如果“codeDetailrule与”R01＃1和R01＃2相同，我想从输入一个数组（1,2）和MIN（orderNo）中的“和”条件中选择那些表，所以首先用“和”消除“condtion喜欢这段代码：

SELECT codeDetailrule, orderNo
FROM detailRuletbl
WHERE id_sym
IN ( 1,2 ) 
GROUP BY codeDetailrule
HAVING COUNT( * ) =2

结果：

| codeDetailRule  | orderNo |
----------------------------
|      R01#1     |    1    |
|      R01#2     |    2    |
|      R02#2     |    2    |
|      R02#3     |    3    |
----------------------------

如果我们使用MIN（orderNO），结果应为：

| codeDetailRule  | orderNo |
----------------------------
|      R01#1     |    1    |----------------------> this is my expect result
|      R02#2     |    2    |
----------------------------

任何人都可以帮助我吗？

直到现在这是我的试用版：

SELECT codeDetailrule, orderNo
FROM detailRuletbl
WHERE id_sym
IN ( 1,2 ) 
GROUP BY codeDetailrule
HAVING COUNT( * ) =2
AND orderNo= ( SELECT MIN( X.orderNo) FROM detailRuletbl,
                (SELECT codeDetailrule, orderNoFROM detailRuletbl
                 WHERE id_sym IN ( 1, 2 ) GROUP BY codeDetailrule
                 HAVING COUNT( * ) =2
                 ) 
                 AS X
               )

和结果：

|  codeDetailrule  | orderNo  |
-------------------------------
|    R01#1         |     1    |
-------------------------------

任何人有什么想法？请帮忙。

Answer 1

SELECT codeDetailrule, orderNo
FROM detailRuletbl
WHERE id_sym
IN ( 1,2 ) AND orderNo IN (
SELECT MIN(orderNo) FROM detailRuletbl
                 GROUP BY orderNo
                 HAVING COUNT(*) = 2
)

如果我误解了你的想法，我很抱歉

Answer 2

我有MIN（）函数的严格答案，并检查“和”condtion

SELECT a.codeRule, a.id_rule, MIN( a.orderNo) 
FROM (ruletbl AS b, detailRuletbl AS a)
INNER JOIN (
             SELECT h.codeDetailrule, h.id_rule AS irule, i.codeRule AS
             krule, MIN( h.oderNo) AS norderno
             FROM detailruletbl AS h, ruletbl AS i
             WHERE h.id_rule = i.id_rule
             AND h.id_sym
             IN ( 1,2 ) 
             GROUP BY h.codeDetailrule
             HAVING COUNT( * ) =2
           )sMin ON a.id_rule= sMin.irule
          GROUP BY sMin.krule

从两个表中选择“和”条件和MIN（）函数

2 个答案: