Question

我在MongoDB中有一个集合“activity_logs”，其中包含以下数据，

{
   "_id": "lg1",
   "action": "create_event",       
   "business_id": "bs1",
   "event_id": "event1",
   "log_date": ISODate("2015-08-20T19:30:46.0Z") 
},
{
       "_id": "lg2",
       "action": "create_deal",       
       "business_id": "bs1",
       "deal_id": "deal1",
       "log_date": ISODate("2015-08-17T19:20:46.0Z") 
},
{
       "_id": "lg3",
       "action": "deal_used",
       "cust_id": "cust1",       
       "business_id": "bs1",
       "deal_id": "deal1",
       "log_date": ISODate("2015-08-17T19:25:46.0Z") 
},
{
       "_id": "lg3",
       "action": "deal_used",
       "cust_id": "cust2",       
       "business_id": "bs1",
       "deal_id": "deal1",
       "log_date": ISODate("2015-08-18T11:25:46.0Z") 
},
{
       "_id": "lg4",
       "action": "create_deal",       
       "business_id": "bs1",
       "deal_id": "deal2",
       "log_date": ISODate("2015-08-18T19:20:46.0Z") 
},
{
       "_id": "lg5",
       "action": "create_deal",       
       "business_id": "bs2",
       "deal_id": "deal3",
       "log_date": ISODate("2015-08-19T19:20:46.0Z") 
},
{
       "_id": "lg6",
       "action": "create_events",       
       "business_id": "bs3",
       "event_id": "event5",
       "log_date": ISODate("2015-07-18T19:22:46.0Z") 
},
{
       "_id": "lg7",
       "action": "deal_used",       
       "business_id": "bs2",
       "cust_id": "cust5"
       "deal_id": "deal3",
       "log_date": ISODate("2015-08-17T19:20:46.0Z") 
}

我想通过该商家采取的一系列行动获取所有记录。最新的第一如果商家创建任何最新的交易，那么我需要显示 xyx创建新的交易1 ，如果2个客户使用该交易，那么我想显示 2个用户使用xyz业务的交易1 。

所以输出看起来像，

business_id       action       deal_id     event_id    users_count    log_date
       bs1         create_event       -         event1     -             ISODate("2015-08-20T19:30:46.0Z") 
       bs2         create_deal      deal3         -    -             ISODate("2015-08-19T19:20:46.0Z")
       bs3         create_event       -         event5    -            ISODate("2015-07-18T19:22:46.0Z")
       bs1         create_deal      deal2         -      -            ISODate("2015-07-18T19:20:46.0Z")
       bs1          deal_used       deal2         -       2            ISODate("2015-07-18T11:25:46.0Z")
       bs1         create_deal      deal1         -        -             ISODate("2015-08-17T19:20:46.0Z")
       bs2          deal_used       deal3         -         -             ISODate("2015-08-17T19:20:46.0Z")

输出将是行动，交易，事件，专业组。

我尝试过以下查询，但这并不满足所有，

db.activity_logs.group({
    "key": {
        "action": true,
        "shared_action": true,
        "business_id": true,
        "event_id": true,
        "deals_id": true,
        "deal_id": true
    },
    "initial": {
        "count_id": 0
    },
    "reduce": function(obj, prev) {
        if (obj._id != null) if (obj._id instanceof Array) prev.count_id += obj._id.length;
        else prev.count_id++;
    }
});

请帮我一样。并建议我如果我可以使用聚合。

Answer 1

经过大量研究后，我发现了我的问题的答案。我发布它只是为了帮助面临这些困难的其他人，

$array = array(
            array('$project' => array( '_id' => 1,'action'=>1, 'business_id'=>1,'event_id' => 1, 'deal_id' => 1, 'cust_id' => 1,'log_date' => 1)),
            array('$group' => array("_id" => array('action' => '$action',"pro_id" => '$pro_id',"event_id" => '$event_id', "deal_id" => '$deal_id'),'count' => array('$sum' => 1),'lastDate' => array( '$last' => '$log_date'))),
            array('$skip'=>$list),
            array('$limit'=>1000),
            array('$sort'=>array('log_date'=> -1)),
        );

        $results = $collection_activity_logs->aggregate($array);

对一个MongoDB查询进行排序和分组

1 个答案: