Question

我正在试图找到此代码中的错误。我已经多次检查过，有人可以指出问题所在吗？

$(function() {
  try {
    function endswith(str, ends) {
      if (ends === '') return true;
      if (str == null || ends == null) return false;
      str = String(str);
      ends = String(ends);
      return str.length >= ends.length && str.slice(str.length - ends.length) === ends;
    }
    var referrer = new URL(document.referrer).domain;
    if (endswith(referrer, "xyz.com")) {
      $(".logo .logo-external").remove();
    } else {
      $(".logo .logo-internal").remove();
    }
  } catch () {}
});

Answer 1

catch (e) {}你错过了变量e

$(function() {
  try {
    function endswith(str, ends) {
      if (ends === '') return true;
      if (str == null || ends == null) return false;
      str = String(str);
      ends = String(ends);
      return str.length >= ends.length && str.slice(str.length - ends.length) === ends;
    }
    var referrer = new URL(document.referrer).domain;
    if (endswith(referrer, "xyz.com")) {
      $(".logo .logo-external").remove();
    } else {
      $(".logo .logo-internal").remove();
    }
  } catch (e) {}
});

Answer 2

根据MDN，try...catch语法的定义类似于以下内容：

try {
   try_statements
}
...
[catch (exception_var) {
   catch_statements
}]
[finally {
   finally_statements
}]

这意味着exception_var不是可选的。否则，它看起来像这样：

...
[catch ([exception_var]) {     // Uncaught SyntaxError: Unexpected token )
   catch_statements
}]
...

catch javascript的意外令牌错误

2 个答案: