下面的代码已经使用了"street": "Manhattan street 15"
,但是我可以如何使用"PL 300"
,因为它们具有相同的名称?
我目前的python代码:
contact_info = dict(business_id=business_id,
name=business_info['name'],
street=address['street'],
post_code=address['postCode'],
city=address['city'],
website=address['website'],
phone=address['phone'],
register_date=register_date
)
这是JSON格式:
"addresses": [
{
"street": "Manhattan street 15",
"postCode": "53100",
"type": 1,
"city": "Monaco",
"country": "MC",
"website": null,
"phone": null,
"fax": null,
"registrationDate": "2014-11-17",
"endDate": null
},
{
"street": "PL 300",
"postCode": "00089",
"type": 2,
"city": "Halic",
"country": "Hc",
"website": null,
"phone": null,
"fax": null,
"registrationDate": "2014-11-17",
"endDate": null
}
]
答案 0 :(得分:1)
json你发布了一个对象数组,所以你必须得到你想要从中获取街道的对象
所以var address =地址[1]; 街道地址= [街道];
你可以进行迭代
答案 1 :(得分:0)
似乎language: node_js
node_js:
- 0.12
为address
,带有两个dicts.So
list
答案 2 :(得分:0)
import json
business_info = json.loads('your.json')
streets = [address['street'] for address in business_info.address]
答案 3 :(得分:0)
尝试:
from urllib2 import urllib
import json
url = 'http://example.com'
response = urlopen(url)
json_obj = json.load(response)
for i in json_obj['addresses']:
print i['street']
它应该工作。它是street
数组中的所有addresses
个名称
对于其他值,您需要指定那些实体名称,就像我为街道
答案 4 :(得分:0)
它是一个包含两个联系人的JSON数组,因此json["address"][0]["street"]
和json["address"][1]["street"]
不同。
import json
contact_infos = []
parsed_json = json.loads(json_string)
for addr in parsed_json["addresses"]:
contact_infos.append(
dict(
business_id=9999,
name="Jason Derulo",
street=addr["street"],
post_code=addr["postCode"],
city=addr["city"],
website=addr["website"],
phone=addr["phone"],
register_date=addr["registrationDate"]
)
)
# A list of two contact infos
print(contact_infos)