Question

Saluton Mundo，我一直致力于此功能，根据数字打印支票上的字样。唯一的问题是我把它变成了一个空白，我不知道如何转换为void-＆gt;串。如果你问我，基本上不可能。简而言之，我如何重写它以便它返回一个字符串。

我的代码如下：

void numALet(string &can)
{
    int conNum= atoi(can.c_str());
    float conNumF= atof(can.c_str());

    //Snippet to find the Cents.
    float cen= (int)((conNumF- conNum)* 100);

    string basic[20]= { " ", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten",
                        "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"},

           diez[9]= { "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};

    if(conNum< 20)
        cout<< basic[conNum]<< " and "<< (cen+ 1) << " Cents.";
    else if(conNum< 100 && conNum> 19)
    {
        int num= conNum% 100;
        if(num% 10!= 0)
            cout<< diez[num/10- 1]<< " "<< basic[num% 10]<< " and "<< (cen+ 1) << " Cents.";
        else
            cout<< diez[conNum/ 10- 1]<< " and "<< (cen+ 1)<< " Cents.";
    }
    else if(conNum> 99 && conNum< 1000)
    {
        int num1= conNum% 1000;
        cout<< basic[num1/ 100]<< " "<< "Hundred ";
        int num2= conNum% 100;

        if(conNum< 20)
            cout<< basic[num2]<< " and "<< (cen+ 1) << " Cents.";
        else if(num2< 100 && num2> 19)
        {
            if(num2% 10!= 0)
                cout<< diez[num2/ 10- 1]<< " "<< basic[num2% 10]<< " and "<< (cen+ 1) << " Cents.";
            else
                cout<< diez[num2/ 10- 1]<< " and "<< (cen+ 1) << " Cents.";
        }
    }
    else if(conNum> 999 && conNum< 10000)
    {
        cout<< basic[conNum/ 1000]<< " "<< "Thousand ";
        int num1= conNum% 1000;
        cout<< basic[num1/ 100]<< " "<< "Hundred ";
        int num2= conNum% 100;

        if(conNum< 20)
            cout<< basic[num2]<< " and "<< cen << " Cents.";
        else if(num2< 100 && num2> 19)
        {
            if(num2% 10!= 0)
                cout<< diez[num2/ 10- 1]<< " "<< basic[num2% 10]<< " and "<< (cen) << " Cents.";
            else
                cout<< diez[num2/ 10- 1];
        }
    }
}

输出：

九千九百九十九和九十九分。

P.S：当调用cen时，它突然返回99,100，这就是为什么我加了+1。

感谢您的帮助。

Answer 1

首先，包括lib：

#include <sstream>

然后，实例化一个std :: stringstream：

std::stringstream ss;

将cout<<替换为ss<<。

最后，将字符串流作为字符串返回。

return ss.str();

检查Writer功能挑战

1 个答案: