我正在尝试从数据库中获取5个属性。我能够获得OneToMany关系的所有4个异常。
Dua.class
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@JoinColumn(name = "DUA_DATA_FIL_ID")
@LazyCollection(LazyCollectionOption.TRUE)
@Fetch(FetchMode.SELECT)
private List<DuaDataFileYearVO> duaDataFileYearList = new ArrayList<DuaDataFileYearVO>();
Hibernate标准
public DuaDataFileShipListObj getDuaInfoForShipping(String duaNumber, DisseminatorListObj disseminatorCodeListObj,
int index) {
DuaDataFileShipListObj dataFileShipList = null;
List<DuaDataFileShipVO> dataFileShipVO = new ArrayList<DuaDataFileShipVO>();
List<DuaDataFileVO> dataFileVOs = new ArrayList<DuaDataFileVO>();
Session session = null;
try {
session = getSessionFactory().openSession();
Criteria criteria = session.createCriteria(DuaDataFileVO.class, "dataFile");
criteria.add(Restrictions.eq("duaNum", duaNumber))
// .add(Restrictions.eq("duaDataFileYearList.duaDataFileId", 677L))
.add(Restrictions.in("dataDisseminatorCode", disseminatorCodeListObj.getDisseminatorCodes()));
criteria.createAlias("dataFile.refDataFileExtractingPCTVO", "refDataFileExtractingPCTVO")
.createAlias("dataFile.refDataFileVO", "refDataFileVO")
.createAlias("dataFile.duaDataFileYearList", "duaDataFileYearList").list();
criteria.setProjection(Projections.projectionList()
.add(Projections.property("duaDataFileId"), "duaDataFileId")
.add(Projections.property("dataDisseminatorCode"), "dataDisseminatorCode")
.add(Projections.property("refDataFileExtractingPCTVO"), "refDataFileExtractingPCTVO")
.add(Projections.property("refDataFileVO"), "refDataFileVO"));
// criteria.setFirstResult(0);
criteria.setMaxResults(index);
criteria.setResultTransformer(Transformers.aliasToBean(DuaDataFileVO.class));
dataFileVOs = criteria.list();
答案 0 :(得分:1)
从第一眼看你的问题看起来你正试图获得财产:duaDataFileYearList
。在您的projectionList中,我没有看到包含此属性,而其他四个属性。
更新:另一种可以实现此目的的方法是获取所需的整个DuaDataFileVO
对象,然后从那里获取DuaDataFileVO.duaDateFileYearList
属性,而不是尝试通过属性获取实体。