给定一组具有两个不同子集的Adts 例如:
sealed trait Domain[Y]
sealed trait Command[Y] extends Domain[Y]
sealed trait Query[Y] extends Domain[Y]
case class Add(value:String) extends Command[Ack]
case class Remove(value:String) extends Command[Ack]
case class Exists(value:String) extends Query[Boolean]
case object List extends Query[List[String]]
现在假设我有两个自然变换,对于一些任意的Monad M [_]:
val commandHandler:Command ~> M
val queryExecutor:Query ~> M
我希望以某种方式将这两种自然变换合并为一个转换:
val service:Domain ~> M = union(commandHandler, queryExecutor)
然而,我们正在努力摆脱较高的副产品。在这个阶段,即使是正确方向的一点也会有所帮助。
答案 0 :(得分:1)
好的,这是一个非常古老的问题,但现在,猫在NaturalTransformation上提供Coproduct
和方法or
:
trait NaturalTransformation[F[_], G[_]] extends Serializable { self =>
def or[H[_]](h: H ~> G): Coproduct[F, H, ?] ~> G = ???
}
所以你可以用它来做(使用kind-projector作为类型lambda ?
)
val combine: Coproduct[Command,Query,?] ~> M = commandHandler.or(queryExecutor)
编辑:以下是一个完整示例,它还定义了union
(使用Id
代替M
进行类型检查):
import cats._
import cats.data._
trait Ack
sealed trait Domain[Y]
sealed trait Command[Y] extends Domain[Y]
sealed trait Query[Y] extends Domain[Y]
case class Add(value:String) extends Command[Ack]
case class Remove(value:String) extends Command[Ack]
case class Exists(value:String) extends Query[Boolean]
case object List extends Query[List[String]]
def commandHandler:Command ~> Id = ???
def queryExecutor:Query ~> Id = ???
def union: Domain ~> Coproduct[Command,Query,?] = new (Domain ~> Coproduct[Command,Query,?]) {
def apply[A](fa: Domain[A]): Coproduct[Command,Query,A] = fa match {
case command: Command[A] => Coproduct.left(command)
case query: Query[A] => Coproduct.right(query)
}
}
def result: Domain ~> Id = commandHandler.or(queryExecutor).compose(union)
或者如果您想避开中间Coproduct
:
def unionDirect[M[_]](cmd: Command ~> M, qry: Query ~> M): Domain ~> M =
new (Domain ~> M) {
def apply[A](fa: Domain[A]): M[A] = fa match {
case command: Command[A] => cmd(command)
case query: Query[A] => qry(query)
}
}
def resultDirect: Domain ~> Id = unionDirect(commandHandler,queryExecutor)