Question

我正在尝试编写一个嵌入了Lua的C程序..而且，我尝试了一个非常简单的程序启动，它只是创建了Lua上下文，然后将其销毁：

import random
count = 0
response = 0
yournum = 0
print("Hello! Welcome to the Lottery Picker \n ")
print("Hit the letter P to pick each line or any other letter to quit ")
response = input()
while count < 6:
#response = 0
     if  yournum == 0 and response == "P":
         number = random.randint(1, 49)
         print("Your first number is: " + str(number))         
         count = count + 1
         yournum = yournum + 1      
         print("Hit the letter P to another number ")
     #response = 0  
         response = input()        
     elif yournum == 1 and response == "P":
         number = random.randint(1, 49)
         print("Your second number is: " + str(number))         
         count = count + 1
         yournum = yournum + 1 
         print("Hit the letter P to another number ")
     #response = 0  
         response = input()        
     elif yournum == 2 and response == "P":
         number = random.randint(1, 49)
         print("Your third number is: " + str(number))         
         count = count + 1   
         yournum = yournum + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input() 
     elif yournum == 3 and response == "P":
         number = random.randint(1, 49)
         print("Your fourth number is: " + str(number))         
         count = count + 1  
         yournum = yournum + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input() 
     elif yournum == 4 and response == "P":
         number = random.randint(1, 49)
         print("Your fifth number is: " + str(number))         
         count = count + 1
         yournum = yournum + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input() 
     elif yournum == 5 and response == "P":
         number = random.randint(1, 49)
         print("And your powerball number is: " + str(number))      
         count = count + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input()          
     else:
         count = count + 1
         print("Something is wrong with the lottery picker - goodbye ")

我正在编译它:(我实际上正在使用Torch7，所以..）

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
extern "C" {
    #include <lua.h>
    #include <lauxlib.h>
    #include <lualib.h>
}

int main(int argc, char *argv[]) {
    lua_State *L = lua_open();
    luaL_openlibs(L);

    lua_close(L);
    fprintf(stderr, "%s: %d\n", __FILE__, __LINE__);
    return(0);
}

当我自己运行时，会打印

g++ -c -g3 -O2 -Wall -Werror -I/usr/local/torch/install/include/ -fPIC pure_lua_test.C -o pure_lua_test.o
g++ -g3 -O2 -Wall -Werror -I/usr/local/torch/install/include/ -fPIC -o pure_lua_test pure_lua_test.o -L/usr/local/torch/install/lib/ -lluajit

如预期的那样（在返回之前）。

但是，当我用valgrind运行时，（如valgrind ./pure_lua_test）

我得到了

pure_lua_test.C: 16

有谁知道发生了什么？为什么在valgrind中使用SIGSEGV？这是我应该担心的吗？基本上，我希望验证我为Torch编写的插件没有内存泄漏......但是，如果它失败了，那么，我有点卡住了。

Answer 1

这个问题的原因似乎是Valgrind，而不是LuaJIT。 Valgrind是blocking MAP_32BIT which breaks LuaJIT。要进行演示，请在NULL上添加对lua_State * L的检查，您会在Valgrind下运行时看到它为NULL，而在定期运行时则为非NULL。

以下是我对您的示例所做的修改：

if(L == NULL) {
    printf("Could not create luaL_newstate()\n");
} else {
    luaL_openlibs(L);
    lua_close(L);
    printf("I can create luaL_newstate fine!\n");
}

当我正常运行时：

$ ./pure_lua_test 
I can create luaL_newstate fine!

但是当我在Valgrind下运行时：

$ valgrind ./pure_lua_test
==8211== Memcheck, a memory error detector
==8211== Copyright (C) 2002-2013, and GNU GPL'd, by Julian Seward et al.
==8211== Using Valgrind-3.10.1 and LibVEX; rerun with -h for copyright info
==8211== Command: ./pure_lua_test
==8211== 
Could not create luaL_newstate()
==8211==

GDB还报告应用程序应该退出：

(gdb) run
Starting program: /tmp/pure_lua_test 
I can create luaL_newstate fine!
[Inferior 1 (process 8621) exited normally]

这是一个完整的MCVE：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
extern "C" {
        #include <lua.h>
        #include <lauxlib.h>
        #include <lualib.h>
}

int main(int argc, char *argv[]) {
    lua_State *L;
    L = luaL_newstate();

    if(L == NULL) {
        printf("Could not create luaL_newstate()\n");
    } else {
        luaL_openlibs(L);

        lua_close(L);
        printf("I can create luaL_newstate fine!\n");
    }

    return(0);
}

Here是一篇关于MAP_32BIT的好文章。希望这会有所帮助。

Lua C API内存泄漏？（Valgrind的）

1 个答案:

Lua C API内存泄漏？ （Valgrind的）

1 个答案:

Lua C API内存泄漏？（Valgrind的）