这是我第一次发帖。以下代码出错,我无法弄清楚原因。我是PHP的新手;我希望得到一些有助于我将来使用php代码的建设性帮助......
这是错误:
解析错误:语法错误,意外'');'(T_CONSTANT_ENCAPSED_STRING)在第6行的C:\ xampp \ htdocs \ EM420_KeyAssignmentsWebsite \ includes \ tables.php
谢谢
<?php
$con=mysqli_connect("localhost","student","scholar",“thrifty_r_us");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL:" .
mysqli_connect_error('mysqli_connect_errno');
}
$sql="CREATE TABLE Customers(ID INT NOT NULL AUTO_INCREMENT, PRIMARY
KEY(ID), FirstName VARCHAR(100),LastName VARCHAR(100),EmailAddress
VARCHAR(100))";
if (mysqli_query($con,$sql));
{
echo "Table Customers created successfully";
}
else
{
echo"Error creating table: " . mysqli_error($con);
}
$sql="CREATE TABLE Clothing(Item_ID INT NOT NULL AUTO_INCREMENT, PRIMARY
KEY(Item_ID), Type VARCHAR(100),Style VARCHAR(100),Size VARCHAR(100),Price
VARCHAR(100),Male_or_Female(100)
)";
if (mysqli_query($con,$sql))
{
echo "Table Clothing created successfully";
}
else
{
echo "Error creating table: " . mysqli_error($con);
}
$sql="CREATE TABLE Books(Book_ID INT NOT NULL AUTO_INCREMENT, PRIMARY
KEY(Book_ID), Title VARCHAR(100),Author VARCHAR(100),Genre
VARCHAR(100),Price VARCHAR(100)
)";
if (mysqli_query($con,$sql))
{
echo "Table Books created successfully";
}
else
{
echo "Error creating table: " . mysqli_error($con);
}
$sql="CREATE TABLE Linens(Item_ID INT NOT NULL AUTO_INCREMENT, PRIMARY
KEY(Item_ID), Type VARCHAR(100),Color VARCHAR(100),Size VARCHAR(100),Price
VARCHAR(100)
)";
if (mysqli_query($con,$sql))
{
echo "Table Linens created successfully";
}
else
{
echo "Error creating table: " . mysqli_error($con);
}
$sql="CREATE TABLE Jewelry(Item_ID INT NOT NULL AUTO_INCREMENT, PRIMARY
KEY(Item_ID), Type VARCHAR(100),Metal VARCHAR(100),Stone
VARCHAR(100),Color
VARCHAR(100),Price VARCHAR(100)
)";
if (mysqli_query($con,$sql))
{
echo "Table Jewelry created successfully";
}
else
{
echo "Error creating table: " . mysqli_error($con);
}
?>