Question

我编写了以下SQL查询，该查询提供每位员工total天数。

SELECT DISTINCT
  ([Entered_By]),
  SUM(ALL DATEDIFF(DAY, Time_End_UTC, Date_Entered_UTC)) OVER (PARTITION BY entered_by) AS Days

FROM [dbo].[Time_Entry]
WHERE date_start BETWEEN '06-01-2015' AND '06-30-2015'
AND DATEDIFF(DAY, Time_End_UTC, Date_Entered_UTC) > 2

我也可以改变＆＃34; sum＆＃34;到＆＃34; count＆＃34; （并删除＆＃34; all＆＃34;）并获取总记录数。

但是我需要以下其中一项：

带有sum的列和带有count的列（请记住我无法写入此数据库）或
总和乘以计数

当我尝试同时拥有(option 1)时，我遇到了问题。我无法弄清楚如何让multiplication (option 2)发挥作用。

感谢您的帮助。

Answer 1

我觉得使用GROUP BY查询而不是窗口sum更容易实现这一点：

Select [Entered_By]
,sum(datediff(Day, Time_End_UTC, Date_Entered_UTC))
,count(*) --count of all records in the group, which you could also multiply by the sum if you prefer option 2

From [dbo].[Time_Entry]
where date_start between '06-01-2015' and '06-30-2015'
and datediff(DAY, Time_End_UTC, Date_Entered_UTC) >2
GROUP BY [Entered_By] --this takes care of the distinctness of [Entered_By] and partitioning you had in your original query

Answer 2

对于选项2，您可以

SELECT COUNT(ATTRIB) * SUM(ATTRIB) FROM TABLE;

MS SQL - 总和然后除以计数

2 个答案: