Question

我正在尝试使用Python和Glade创建一个基本的文件传输GUI应用程序，并且在尝试从“文件选择器”对话框中获取路径时遇到了一些障碍。我已经尝试了所有我知道但可以找到的但是没有成功。

.glade文件很长，所以我在这里发布了代码：http://pastebin.com/wsdLMenC

我的Python代码看起来像这样

import datetime
from ftplib import FTP
from magip import *
from gi.repository import Gtk

class FTP():
    def __init__(self):
        self.builder = Gtk.Builder()
        self.builder.add_from_file("ftp.glade")

        go = self.builder.get_object

        self.window = go("window1")
        self.store_magazine = go("store_magazine")
        self.combo_magazine = go("combo_magazine")
        self.store_luni = go("store_luni")
        self.combo_luni = go("combo_luni")
        self.select_folder = go("select_folder")
        self.btn_start = go("btn_start")

        for ip in magazine:
            self.store_magazine.append([magazine[ip]])

        if host in magazine:
            self.combo_magazine.set_active(magip_index[host])

        for luna in luni:
            self.store_luni.append([luni[luna]])

        self.builder.connect_signals(Handlers())
        self.window.show_all()


class Handlers():
    def btn_start_clicked(self, button):
        with open("btn.txt", "a") as muhfile:
            text = "click {}\n".format(datetime.datetime.now())
            muhfile.write(text)


if __name__ == "__main__":
    gui = FTP()
    Gtk.main()

Handlers类是我想放置所有信号的地方。目前只有一个，用于测试START按钮。

非常感谢任何帮助。

谢谢！

Answer 1

您必须连接到＆＃34;文件集＆＃34;信号。处理程序类看起来像这样：

class Handlers():
    def btn_start_clicked(self, button):
        with open("btn.txt", "a") as muhfile:
            text = "click {}\n".format(datetime.datetime.now())
            muhfile.write(text)

    def directory_set(self, button):
        print(button.get_filename())

和Glade文件中的FileChooserButton如下：

    <child>
      <object class="GtkFileChooserButton" id="select_folder">
        <property name="visible">True</property>
        <property name="can_focus">False</property>
        <property name="action">select-folder</property>
        <property name="create_folders">False</property>
        <property name="preview_widget_active">False</property>
        <property name="use_preview_label">False</property>
        <property name="title" translatable="yes">Select folder</property>
        <signal name="file-set" handler="directory_set" swapped="no"/>
      </object>
      <packing>
        <property name="left_attach">0</property>
        <property name="top_attach">3</property>
      </packing>
    </child>

从Python中的FileChooserButton获取文件夹路径

1 个答案: