我以这种方式添加了一个ChildViewController,它打开了屏幕的一半。
function parseBinary(str) {
var i, value = 0;
for (i = 0; i < str.length; ++i)
value = value * 2 + +str[i];
return value;
}
关于ChildView的解雇我叫这个:
m_customStartupView = [[CustomStartUpViewController alloc]init];
m_customStartupView.delegate = self;
if(m_showStatus == SHOW_STATUS)
{
m_customStartupView.dialogToShow = LAST_SYNC_STATUS;
}
[self addChildViewController:m_customStartupView];
[[self view] addSubview:[m_customStartupView view]];
[m_customStartupView didMoveToParentViewController:self];
CGRect rect = m_customStartupView.view.frame;
if(IPHONE_5)
{
rect.origin.y = 568;
}
else
{
rect.origin.y = 480;
}
m_customStartupView.view.frame = rect;
[UIView beginAnimations:@"ShowView" context:nil];
[UIView setAnimationCurve:UIViewAnimationCurveEaseInOut];
[UIView setAnimationDuration:0.2];
if(IPHONE_5)
{
rect.origin.y = 520;
}
else
{
rect.origin.y = 420;
}
m_customStartupView.view.frame = rect;
[UIView commitAnimations];
所以我有两个按钮,按钮1和按钮2,当用户点击按钮1时,一个childView从底部动画显示。现在,如果用户按下按钮2,则解除之前的childView,然后显示新的childView
所以问题是如果我非常快地点击两个按钮,比如播放一个casio,那么childViews会重叠。
1)我们如何解决这个问题。
2)我是否正确地做了
此致 兰吉特
答案 0 :(得分:0)
尝试在动画播放过程中暂时禁用按钮2:
[button2 setEnabled:NO]
然后在动画结束时将其反转:
[button2 setEnabled:YES]