Question

我有一个Bootstrap single-button dropdown，我想点击使用Protractor在下拉列表中显示的其中一个选项。我该如何做到这一点？

               <div class="btn-group" ng-if="!persist.edit" dropdown>
                    <button type="button"
                            class="btn btn-default"
                            dropdown-toggle>
                        <span translate="GENERAL.ACTIONS"></span>
                        <span class="caret"></span>
                    </button>
                    <ul class="dropdown-menu" role="menu">

                        <!-- Check In -->
                        <li role="presentation">
                            <a ng-click="checkIn()"
                               role="menuitem"
                               tabindex="-1"
                               translate="ITEMS.LIST.BUTTON_CHECK_ITEM_IN">
                            </a>
                        </li>


                        <!-- Check Out -->
                        <li role="presentation"">
                            <a ng-click="checkOut()"
                               role="menuitem"
                               tabindex="-1"
                               translate="ITEMS.LIST.BUTTON_CHECK_ITEM_OUT"
                               translate-value-length="1">
                            </a>
                        </li>
                    </ul>
                </div>

我试过这个（调用下拉列表，但点击失败）：

it('Should click Actions button and show dropdown', function(){
    element(by.buttonText("Actions")).click(); 
    browser.sleep(1000);
});
it('Should click the Check Item Out dropdown option and change status to checked out', function(){
    element(by.css('[value="ITEMS.LIST.BUTTON_CHECK_ITEM_OUT"]')).click();
});

Answer 1

首先，点击＆＃34;下拉切换＆＃34;按钮打开下拉列表。然后，选择一个选项：

var dropDown = element(by.css("div[dropdown]"));
dropDown.element(by.css("button[dropdown-toggle]")).click(); 
dropDown.element(by.css("a[ng-click*=checkIn]")).click();  // Check In

工作代码：

    element(by.buttonText("Actions")).click(); 
    element(by.css('[ng-click="]checkIn()"]')).click();  // Check In

Answer 2

从Bootstrap Dropdown中选择一个干净的解决方案是按buttonText然后按linkText：

element(by.buttonText('your button')).click();
element(by.linkText('your selection')).click();

量角器 - 从Bootstrap Dropdown中选择

2 个答案: