[
{"id":1,"countryname":"India","zoneid":"1","countryid":"1","zonename":"South","stateid":"1","zid":"1","statename":"Karnataka"},
{"id":1,"countryname":"India","zoneid":"1","countryid":"1","zonename":"South","stateid":"2","zid":"1","statename":"Karnataka"},
{"id":1,"countryname":"India","zoneid":"1","countryid":"1","zonename":"South","stateid":"3","zid":"1","statename":"Karnataka"},
{"id":1,"countryname":"India","zoneid":"2","countryid":"1","zonename":"East","stateid":"4","zid":"2","statename":"Karnataka"},
{"id":2,"countryname":"UK","zoneid":"3","countryid":"2","zonename":"West","stateid":"5","zid":"3","statename":"Karnataka"},
{"id":3,"countryname":"Australia","zoneid":"3","countryid":"3","zonename":"West","stateid":"6","zid":"3","statename":"Karnataka"},
{"id":3,"countryname":"Australia","zoneid":"4","countryid":"3","zonename":"North","stateid":"7","zid":"4","statename":"Karnataka"},
{"id":4,"countryname":"Sweedan","zoneid":null,"countryid":null,"zonename":null}
]
答案 0 :(得分:0)
使用JSON.parse(你的json字符串)
转到docs
答案 1 :(得分:0)
angular.fromJson(string)
和angular.toJson(object/array)
答案 2 :(得分:0)
您需要规范化您的数据,以便国家/地区的相关记录位于子集合下,如下所示:
[
{
"id": 1,
"countryname": "India",
"zones": [
{
"zoneid": 1,
"zonename": "South",
"states": [
{
"stateid": 1,
"statename": "Karnataka"
}
]
},
{
"zoneid": 2,
"zonename": "East",
"states": [
{
"stateid": 1,
"statename": "Karnataka"
}
]
}
]
},
{
"id": 2,
"countryname": "UK",
"zones": [
{
"zoneid": "3",
"zonename": "West",
"states": [
{
"stateid": "5",
"statename": "Karnataka"
}
]
}
]
}
]
如果您的数据是字符串,则需要通过JSON.parse将其转换为JSON,如前面的答案所述。从那里(如果您无法在服务器端规范化数据),您可以访问属性以像普通对象一样构建规范化的JSON。有几种方法可以构建“新的”JSON数组,但希望这是您的起点。如果您仍然遇到问题,我可以指出您的方法。