这是我对Ajax库的可能。但那似乎已经过时了?
答案 0 :(得分:0)
据我所知,没有理由不使用jQuery的microsoft ajax客户端javascript库。
我认为你可以正常访问它。试试这个,看它是否有效。请参阅上面提到的microsoft ajax库和jQuery库。
$(document).ready(function () {
Type.registerNamespace("Demo");
Demo.Person = function(firstName, lastName, emailAddress) {
this._firstName = firstName;
this._lastName = lastName;
this._emailAddress = emailAddress;
}
Demo.Person.prototype = {
getFirstName: function() {
return this._firstName;
},
getLastName: function() {
return this._lastName;
},
getEmailAddress: function() {
return this._emailAddress;
},
setEmailAddress: function(emailAddress) {
this._emailAddress = emailAddress;
},
getName: function() {
return this._firstName + ' ' + this._lastName;
},
dispose: function() {
alert('bye ' + this.getName());
},
sendMail: function() {
var emailAddress = this.getEmailAddress();
if (emailAddress.indexOf('@') < 0) {
emailAddress = emailAddress + '@example.com';
}
alert('Sending mail to ' + emailAddress + ' ...');
},
toString: function() {
return this.getName() + ' (' + this.getEmailAddress() + ')';
}
}
Demo.Person.registerClass('Demo.Person', null, Sys.IDisposable);
Demo.Employee = function(firstName, lastName, emailAddress, team, title) {
Demo.Employee.initializeBase(this, [firstName, lastName, emailAddress]);
this._team = team;
this._title = title;
}
Demo.Employee.prototype = {
getTeam: function() {
return this._team;
},
setTeam: function(team) {
this._team = team;
},
getTitle: function() {
return this._title;
},
setTitle: function(title) {
this._title = title;
},
toString: function() {
return Demo.Employee.callBaseMethod(this, 'toString') + '\r\n' + this.getTitle() + '\r\n' + this.getTeam();
}
}
Demo.Employee.registerClass('Demo.Employee', Demo.Person);
});