我有一个
形式的json[
{
"foo":"bar"
}
]
我正在尝试使用logstash中的json过滤器对其进行过滤。但它似乎没有用。我发现我无法使用logstash中的json过滤器解析列表json。有人可以告诉我有关解决方法吗?
更新
我的日志
IP - - 0.000 0.000 [24/May/2015:06:51:13 +0000] *"POST /c.gif HTTP/1.1"* 200 4 * user_id=UserID&package_name=SomePackageName&model=Titanium+S202&country_code=in&android_id=AndroidID&eT=1432450271859&eTz=GMT%2B05%3A30&events=%5B%7B%22eV%22%3A%22com.olx.southasia%22%2C%22eC%22%3A%22appUpdate%22%2C%22eA%22%3A%22app_activated%22%2C%22eTz%22%3A%22GMT%2B05%3A30%22%2C%22eT%22%3A%221432386324909%22%2C%22eL%22%3A%22packageName%22%7D%5D * "-" "-" "-"
以上日志的URL解码版本是
IP - - 0.000 0.000 [24/May/2015:06:51:13 0000] *"POST /c.gif HTTP/1.1"* 200 4 * user_id=UserID&package_name=SomePackageName&model=Titanium S202&country_code=in&android_id=AndroidID&eT=1432450271859&eTz=GMT+05:30&events=[{"eV":"com.olx.southasia","eC":"appUpdate","eA":"app_activated","eTz":"GMT+05:30","eT":"1432386324909","eL":"packageName"}] * "-" "-" "-"
请在下面的配置文件中找到以上日志..
过滤{
urldecode{
field => "message"
}
grok {
match => ["message",'%{IP:clientip}%{GREEDYDATA} \[%{GREEDYDATA:timestamp}\] \*"%{WORD:method}%{GREEDYDATA}']
}
kv {
field_split => "&? "
}
json{
source=> "events"
}
geoip {
source => "clientip"
}
}
我需要解析事件,即events=[{"eV":"com.olx.southasia","eC":"appUpdate","eA":"app_activated","eTz":"GMT+05:30","eT":"1432386324909","eL":"packageName"}]
答案 0 :(得分:5)
我假设你的json在一个文件中。你是对的,你不能直接使用json过滤器。您必须使用多行编解码器,然后使用json过滤器。
以下配置适用于您的输入。但是,您可能需要更改它才能正确分隔事件。这取决于您的需求和文件的json格式。
Logstash config:
input {
file {
codec => multiline
{
pattern => "^\]" # Change to separate events
negate => true
what => previous
}
path => ["/absolute/path/to/your/json/file"]
start_position => "beginning"
sincedb_path => "/dev/null" # This is just for testing
}
}
filter {
mutate {
gsub => [ "message","\[",""]
gsub => [ "message","\n",""]
}
json { source => message }
}
更新后,我猜我发现了问题。显然,由于方括号,你得到了一个 jsonparsefailure 。作为解决方法,您可以手动删除它们。在kv之后和json过滤器之前添加以下mutate过滤器:
mutate {
gsub => [ "events","\]",""]
gsub => [ "events","\[",""]
}
好吧,假设您的输入如下:
[{"foo":"bar"},{"foo":"bar1"}]
以下是4个选项:
选项a)丑陋的gsub
一个丑陋的解决方法是另一个gsub:
gsub => [ "event","\},\{",","]
但这会消除内在关系,所以我猜你不想这样做。
选项b)拆分
更好的方法可能是使用拆分过滤器:
split {
field => "event"
terminator => ","
}
mutate {
gsub => [ "event","\]",""]
gsub => [ "event","\[",""]
}
json{
source=> "event"
}
这将生成多个事件。 (首先是foo = bar
,第二个是foo1 = bar1
。)
选项c)改变分裂
您可能希望在一个logstash事件中包含所有值。你可以使用 mutate =>拆分过滤器以生成数组并在条目存在时解析json。不幸的是,你必须为每个条目设置一个条件,因为logstash不支持其配置中的循环。
mutate {
gsub => [ "event","\]",""]
gsub => [ "event","\[",""]
split => [ "event", "," ]
}
json{
source=> "event[0]"
target => "result[0]"
}
if 'event[1]' {
json{
source=> "event[1]"
target => "result[1]"
}
if 'event[2]' {
json{
source=> "event[2]"
target => "result[2]"
}
}
# You would have to specify more conditionals if you expect even more dictionaries
}
选项d)Ruby
根据你的评论,我试图找到一种红宝石的方式。以下工作(在您的kv过滤器之后):
mutate {
gsub => [ "event","\]",""]
gsub => [ "event","\[",""]
}
ruby {
init => "require 'json'"
code => "
e = event['event'].split(',')
ary = Array.new
e.each do |x|
hash = JSON.parse(x)
hash.each do |key, value|
ary.push( { key => value } )
end
end
event['result'] = ary
"
}
选项e)Ruby
在kv过滤器之后使用此方法(不设置mutate过滤器):
ruby {
init => "require 'json'"
code => "
event['result'] = JSON.parse(event['event'])
"
}
它将解析event=[{"name":"Alex","address":"NewYork"},{"name":"David","address":"NewJersey"}]
成:
"result" => [
[0] {
"name" => "Alex",
"address" => "NewYork"
},
[1] {
"name" => "David",
"address" => "NewJersey"
}
由于kv过滤器的行为不支持空格。我希望你没有真正的投入,是吗?