Question

早上好 - 我正在使用以下YouTube教程Tutoriel PHP - Importer des contacts Google尝试导入Google联系人。

当我点击链接导入Google通讯录时，我收到以下错误，而不是要求获得许可并获取联系人并在屏幕上显示这些联系人：

警告：缺少Google_Client :: authenticate（）的参数1，名为   在第34行的/var/www/html/restaurant_test/index.php中定义   /var/www/html/restaurant_test/lib/google-api-client/Google_Client.php   在第124行

注意：未定义的变量：代码输入   /var/www/html/restaurant_test/lib/google-api-client/Google_Client.php   在第127行

致命错误：带有消息的未捕获异常'Google_Auth_Exception'   '无效代码'   /var/www/html/restaurant_test/lib/google-api-client/Auth/OAuth2.php:88   堆栈跟踪：＃0   /var/www/html/restaurant_test/lib/google-api-client/Google_Client.php(127）：   Google_Auth_OAuth2-＆gt; authenticate（NULL，false）＃1   /var/www/html/restaurant_test/index.php(34）：   Google_Client-＆gt; authenticate（）＃2 {main}引入   /var/www/html/restaurant_test/lib/google-api-client/Auth/OAuth2.php on   第88行

请告诉我该怎么做以修复错误。谢谢。

这是我的代码：

<?php 
error_reporting(E_ALL);
ini_set("display_errors", 1);

session_start(); ?>
<!DOCTYPE html>
<html class="no-js" lang="en"/>
<head>
    <meta charset="utf-8" />
    <meta name="viewport" content="width=device-width" />
    <title>Google Contacts API</title>
</head>

<body>
<h2>Google Contacts API v3.0</h2>
<?php
require_once 'lib/google-api-client/autoload.php';
require 'lib/google-api-client/Config.php';
require 'lib/google-api-client/Google_Client.php';

$client_id = 'aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa.bbbbbb.cccccccccccc.com';
$client_secret = 'oUe3fsfds4gfg23ha93kmKFkfgKZ';
$redirect_uri = 'http://ccccccccccccccccccc.com/rddddddddddd/index.php';

$client = new Google_Client();
$client -> setApplicationName('contact');
$client -> setClientid($client_id);
$client -> setClientSecret($client_secret);
$client -> setScopes('https://www.google.com/m8/feeds');
$client -> setRedirectUri($redirect_uri);
$client -> setAccessType('online');

if (isset($_GET['code'])) {
    $client->authenticate();
    $_SESSION['token'] = $client->getAccessToken();
    header('Location: ' . $redirect_uri);
}

if(!isset($_SESSION['token']))
{
    $url = $client->createAuthUrl();
    echo '<a href="' . $url . '">Import Google Contacts</a>';
}else{
        $client->setAccessToken($_SESSION['token']);
        $token = json_decode($_SESSION['token']);
        $token->access_token;
        $curl = curl_init("https://www.google.com/m8/feeds/contacts/default/full?alt=json&max-results=50&access_token=" . $token->access_token);
        curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);
        curl_setopt($curl, CURLOPT_TIMEOUT, 10);
        $contacts_json = curl_exec($curl);
        curl_close($curl);
        $contacts = json_decode($contacts_json, true);
        $return = array();
        foreach($contacts['feed']['entry'] as $contact){
            $return[] = array(
            'name' => $contact['title']['$t'],
            'email' => isset($contact['gd$email'][0]['address']) ? $contact['gd$email'][0]['address'] : false,
            'phone' => isset($contact['gd$phoneNumber'][0]['$t']) ? $contact['gd$phoneNumber'][0]['$t'] :false,
            );
        }
        var_dump($return);
    }       
?>

</body>
</html>

Answer 1

您似乎忘记了将code传递给authenticate方法。以下是Google_Client.php中authenticate方法的文档和实施：

/**
 * Attempt to exchange a code for an valid authentication token.
 * If $crossClient is set to true, the request body will not include
 * the request_uri argument
 * Helper wrapped around the OAuth 2.0 implementation.
 *
 * @param $code string code from accounts.google.com
 * @param $crossClient boolean, whether this is a cross-client authentication
 * @return string token
 */
public function authenticate($code, $crossClient = false)
{
  $this->authenticated = true;
  return $this->getAuth()->authenticate($code, $crossClient);
}

因此，更改以下代码很可能会解决问题：

if (isset($_GET['code'])) {
    $client->authenticate($_GET['code']); // <-- Add code parameter here
    $_SESSION['token'] = $client->getAccessToken();
    header('Location: ' . $redirect_uri);
}

导入Google联系人时出现OAuth问题

1 个答案: