Question

我知道已经提出了几个类似的问题，但答案都包括已弃用的解决方案。

我已经开始在android上开发一个应用程序，它显示一些关于通知的信息（始终保持开启状态），我希望用户能够通过点击通知来访问应用程序。

以下是我所做的工作，当我点击通知（显示正确）时没有任何操作

我有一个名为SendNotification的方法，它由按键调用，除了调用

之外几乎没有

private void DispatchNotification(String numValue,String nameValue){
        Intent intent=new Intent(this,MainActivity.class);
        PendingIntent pIntent=PendingIntent.getActivity(this,0,intent,PendingIntent.FLAG_UPDATE_CURRENT);

        NotificationCompat.Builder builder= new NotificationCompat.Builder(this);
        builder.setAutoCancel(false);
        builder.setContentTitle("Just Title");
        builder.setContentText(nameValue+" "+numValue);
        builder.setSmallIcon(R.drawable.abc_popup_background_mtrl_mult);
        Notification notification = builder.build();
        notification.flags|= Notification.FLAG_ONGOING_EVENT;
        builder.addAction(R.drawable.abc_popup_background_mtrl_mult,"MENU",null);
        builder.setContentIntent(pIntent);
        NotificationManager manager = (NotificationManager)this.getSystemService(NOTIFICATION_SERVICE);
        manager.notify(8,notification);
    }

提前致谢。

Answer 1

根据documentation，您可以通过打开活动来构建通知：

NotificationCompat.Builder mBuilder =
    new NotificationCompat.Builder(this)
    .setSmallIcon(R.drawable.notification_icon)
    .setContentTitle("My notification")
    .setContentText("Hello World!");

Intent resultIntent = new Intent(this, ResultActivity.class);

// Because clicking the notification opens a new ("special") activity, there's
// no need to create an artificial back stack.
PendingIntent resultPendingIntent =
    PendingIntent.getActivity(
    this,
    0,
    resultIntent,
    PendingIntent.FLAG_UPDATE_CURRENT
);

mBuilder.setContentIntent(resultPendingIntent);
// Sets an ID for the notification
int mNotificationId = 001;
// Gets an instance of the NotificationManager service
NotificationManager mNotifyMgr = 
        (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
// Builds the notification and issues it.
mBuilder.setOngoing(true);
mNotifyMgr.notify(mNotificationId, mBuilder.build());

Answer 2

第1步：摆脱现有的builder.build()电话。

第2步：将notification.flags|= Notification.FLAG_ONGOING_EVENT;替换为builder.setOngoing(true);。

第3步：将manager.notify(8,notification)替换为manager.notify(8, builder.build());

I，在完成Notification之前，您正在构建Builder。

Answer 3

试试这个：

  Intent intent = new Intent(ctx, MainActivity.class);
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP |Intent.FLAG_ACTIVITY_SINGLE_TOP|Intent.FLAG_ACTIVITY_CLEAR_TASK );
    PendingIntent pendingIntent = PendingIntent.getActivity(ctx, 0 /* Request code */, intent, PendingIntent.FLAG_ONE_SHOT|PendingIntent.FLAG_UPDATE_CURRENT);

    Uri defaultSoundUri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
    NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(ctx)
            .setSmallIcon(R.drawable.icon_notification)
            .setContentTitle("Your app name")
            .setContentText(message)
            .setAutoCancel(true)
            .setSound(defaultSoundUri)
            .setContentIntent(pendingIntent);

    NotificationManager notificationManager =
            (NotificationManager) ctx.getSystemService(Context.NOTIFICATION_SERVICE);

    notificationManager.notify(0 /* ID of notification */, notificationBuilder.build());

通过点击通知显示应用程序

3 个答案: