Question

我有一个显示整个月的表 - 这样的票证打开开始日期（2015-07-28 06:40:52:337）和票据结束结束日期（2015-07-29 07:45:52:337）。

使用T-SQL DATEDIFF()我想找出DAYS，HOURS，MINUTES和SECS之间的区别，并将其放入新的计算列名为TimeDiff。

我该如何做到这一点？

Answer 1

使用DATEDIFF

SELECT  CAST(DATEDIFF(DAY, [Opened Start Date], [Close End Date]) AS VARCHAR(5)) + ' Day(s), ' +
        CAST(DATEDIFF(HOUR, [Opened Start Date], [Close End Date]) AS VARCHAR(5)) + ' Hour(s), ' +
        CAST(DATEDIFF(MINUTE, [Opened Start Date], [Close End Date]) AS VARCHAR(5)) + ' Minute(s), ' +
        CAST(DATEDIFF(SECOND, [Opened Start Date], [Close End Date]) AS VARCHAR(5)) + ' Second(s), ' AS TimeDiff
FROM yourTable

Answer 2

你可能需要这样的东西：

CREATE TABLE Table1
(
    [starttime] datetime, [endtime] datetime,
    TimeDiff as 
    convert(varchar(3), (DATEDIFF(SECOND, [starttime], [endtime])/86400)) + ' Days, ' +
    convert(varchar(2), ((DATEDIFF(SECOND, [starttime], [endtime])%86400)/3600)) + ' Hours, ' +
    convert(varchar(2), (((DATEDIFF(SECOND, [starttime], [endtime])%86400)%3600)/60)) + ' Minutes, ' +
    convert(varchar(2), (((DATEDIFF(SECOND, [starttime], [endtime])%86400)%3600)%60)) + ' Seconds',
);

以秒为单位计算所有差异并计算每个时间部分。

SQL Fiddle

中的示例

使用DATEDIFF（）计算列

2 个答案: