我想在listview

Question

我想在文本字段中的单行显示2个项目，如何在listview的同一行中放置2个项目？

我想要显示这样的内容：

item 1 

item 2|item3

item 4

item 5 | item 6

我的代码：

public class MultipleItemsList extends ListActivity {

    private MyCustomAdapter mAdapter;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        mAdapter = new MyCustomAdapter();
        int count=0;
        for (int i = 1; i < 50; i++) {

            if(count==0){
                mAdapter.addItem("item " + i);
                count++;
            }
            else if (count == 1) {
                mAdapter.addSeparatorItem("item " + i);
                count++;
            }
            else  if(count==2){
                mAdapter.addSeparatorItem1("item "+i);
                count=0;
            }
        }
        setListAdapter(mAdapter);
    }

    private class MyCustomAdapter extends BaseAdapter {

        private static final int TYPE_ITEM = 0;
        private static final int TYPE_SEPARATOR = 1;
        private static final int TYPE_SEPARATOR1=2;
        private static final int TYPE_MAX_COUNT = TYPE_SEPARATOR + 1;

        private ArrayList<String> mData = new ArrayList<String>();
        private LayoutInflater mInflater;

        private TreeSet<Integer> mSeparatorsSet = new TreeSet<Integer>();
        private TreeSet<Integer> mSeparatorSet1=new TreeSet<Integer>();
        public MyCustomAdapter() {
            mInflater = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        }

        public void addItem(final String item) {
            mData.add(item);
            notifyDataSetChanged();
        }

        public void addSeparatorItem(final String item) {
            mData.add(item);
            // save separator position
            mSeparatorsSet.add(mData.size() - 1);
            notifyDataSetChanged();
        }
        public void addSeparatorItem1(final String item){
            mData.add(item);
            mSeparatorSet1.add(mData.size()-1);
            notifyDataSetChanged();
        }

        @Override
        public int getItemViewType(int position) {
            if(mSeparatorsSet.contains(position)){
                return TYPE_SEPARATOR;
            }
            else if(mSeparatorSet1.contains(position)){
                return TYPE_SEPARATOR1;
            }
            else
                return TYPE_ITEM;
        }

        @Override
        public int getViewTypeCount() {
            return TYPE_MAX_COUNT;
        }

        @Override
        public int getCount() {
            return mData.size();
        }

        @Override
        public String getItem(int position) {
            return mData.get(position);
        }

        @Override
        public long getItemId(int position) {
            return position;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            ViewHolder holder = null;
            int type = getItemViewType(position);
            System.out.println("getView " + position + " " + convertView + " type = " + type);
            if (convertView == null) {
                holder = new ViewHolder();
                switch (type) {
                    case TYPE_ITEM:
                        convertView = mInflater.inflate(R.layout.item1, null);
                        holder.textView = (TextView)convertView.findViewById(R.id.text);
                        break;
                    case TYPE_SEPARATOR:
                        convertView = mInflater.inflate(R.layout.item2, null);
                        holder.textView = (TextView)convertView.findViewById(R.id.textSeparator);
                        break;
                    case TYPE_SEPARATOR1:
                        convertView=mInflater.inflate(R.layout.item2,null);
                        holder.textView=(TextView)convertView.findViewById(R.id.textSeparator1);
                        break;
                }
                convertView.setTag(holder);
            } else {
                holder = (ViewHolder)convertView.getTag();
            }
            holder.textView.setText(mData.get(position));
            return convertView;
        }

    }

    public static class ViewHolder {
        public TextView textView;
    }
}

Answer 1

要在一行中显示两个项目，必须使用LinearLayout作为权重1的父项。线性布局的方向必须是水平的。 在线性布局中添加两个重量为0.5的子项。 绝对不是唯一的方法，但它会做你要求的。 希望它有所帮助。

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="horizontal"
    android:weightSum="1" >

    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_weight="0.5"
        android:text="text" />

    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_weight="0.5"
        android:text="text" />

</LinearLayout>

Answer 2

ListView并不真正支持这种操作。 ListView中的项目必须垂直堆叠。而ListView的内部实现将阻止任何简单的尝试来说服它以不同方式放置项目。

查看兼容性库中的GridLayout控件。这很容易涵盖你想要做的事情。