我使用以下代码发送邮件
public function sendMail($mailTo, $subject) {
//$mailTo is an array like array(test1@gmail.com,test2@gmail.com)
$mailto = implode(', ', $mailTo);
$subject = empty($subject) ? 'Testing Manuel Lemos SMTP class' : $subject;
require("smtp.php");
/* Uncomment when using SASL authentication mechanisms */
require("sasl.php");
$from = "mlemos@acm.org"; /* Change this to your address like "me@mydomain.com"; */ $sender_line = __LINE__;
$to = "$mailto";
if ($smtp->SendMessage(
$from,
array($to)
, array(
"From: $from",
"To: $to",
"Subject: TESTMAIL NOTIFICATION",
"Date: " . strftime("%a, %d %b %Y %H:%M:%S %Z")
), "Hello $to,$subject \n Bye .")) {
$str = "Message sent to $to OK.\n";
return $str;
} else
$str = "Could not send the message to $to.\nError: " . $smtp->error . "\n";
}
我在smtp.php中有sendMessage函数,如下所示
Function SendMessage($sender,$recipients,$headers,$body)
{
if(($success=$this->Connect()))
{
if(($success=$this->MailFrom($sender)))
{
for($recipient=0;$recipient<count($recipients);$recipient++)
{
if(!($success=$this->SetRecipient($recipients[$recipient])))
break;
}
if($success
&& ($success=$this->StartData()))
{
for($header_data="",$header=0;$header<count($headers);$header++)
$header_data.=$headers[$header]."\r\n";
$success=($this->SendData($header_data."\r\n")
&& $this->SendData($this->PrepareData($body))
&& $this->EndSendingData());
}
}
$error=$this->error;
$disconnect_success=$this->Disconnect($success);
if($success)
$success=$disconnect_success;
else
$this->error=$error;
}
return($success);
}
但是它没有发送电子邮件,而是发送单个邮件。 当我们将$ to指定为'test@gmail.com'时。请帮忙。
答案 0 :(得分:1)
为什么你implode()
收件人?
似乎SendMessage
可以处理作为数组传递的多个收件人:
$smtp->SendMessage('sender@example.tld', array('test@gmail.com', 'test2@gmail.com') ... );
在SendMessage
中为SetRecipient
中的每个条目调用$recipients
for($recipient=0;$recipient<count($recipients);$recipient++)
{
if(!($success=$this->SetRecipient($recipients[$recipient])))
break;
}
:
HTML
但是,当您处理多个收件人时,应该避免以您的方式传递“收件人”标题。