我有以下内容。有用。我希望以避免使用动态的方式来避免使用类型数量的代码增长为O(n ^ 2)。我所知道的标准双调度解决方案在A,B,C,D类型中都有O(n)代码,导致整体O(n ^ 2)。
有没有理智的方法呢?
public class P {}
public class A: P {}
public class B: P {}
public class C: P {}
public class D: P {}
public class DynamicDispatchLowPriorityMethods
{
// The superclass is to avoid a runtime error when calling Multi(b, a).
// Without something like this, the call is ambiguous.
protected string _Output {get;set;}
public DynamicDispatchLowPriorityMethods()
{
}
public void Multi(P x, P y) {
_Output += "PP ";
}
public void Multi(B x, P y) {
_Output += "bP ";
}
}
[TestFixture()]
public class DynamicDispatch: DynamicDispatchLowPriorityMethods
{
public void Multi(A x, A y) {
_Output += "aa ";
}
public void Multi(A x, P y) {
_Output += "aP ";
}
public void Multi(P x, A y) {
_Output += "Pa ";
}
public void Multi(B x, B y) {
_Output += "bb ";
}
public void Multi(C x, C y) {
_Output += "cc ";
}
public void Multi(D x, D y) {
_Output += "dd ";
}
public void Multi(B x, D y) {
_Output += "bd ";
}
public void DynamicMulti(P x, P y) {
this.Multi((dynamic)x, (dynamic)y);
}
[Test()]
public void TestDynamicDispatch()
{
_Output = "";
P a = new A ();
P b = new B ();
P c = new C ();
P d = new D ();
this.DynamicMulti(a, a);
this.DynamicMulti(a, b);
this.DynamicMulti(a, c);
this.DynamicMulti(a, d);
_Output += "\n";
this.DynamicMulti(b, a);
this.DynamicMulti(b, b);
this.DynamicMulti(b, c);
this.DynamicMulti(b, d);
_Output += "\n";
this.DynamicMulti(c, a);
this.DynamicMulti(c, b);
this.DynamicMulti(c, c);
this.DynamicMulti(c, d);
_Output += "\n";
this.DynamicMulti(d, a);
this.DynamicMulti(d, b);
this.DynamicMulti(d, c);
this.DynamicMulti(d, d);
CommonDebug.WriteLine(_Output);
}
}
输出是:
aa aP aP aP
Pa bb bP bd
Pa PP cc PP
Pa PP PP dd
有关背景信息,请参阅this question有关双重调度的替代方法。