Question

目前我可以遍历我的JSON数组'' pos “并将其中的所有变量存储到数组列表中。

我正在尝试做什么：

如何轻松解析 tour＆amp;日期哪些在“ pos ”数组之外？

我想将值存储在“ tour ”＆amp; “日期”分为两个独立的字符串变量。

我的理解： json.getJSONArray（）在这种情况下不能用作json.getJSONArray（TAG_MESSAGES）;只拉入“pos”数组数据。

JSON结构：

{
    "pos": [
        {
            "pos": "",
            "person": "",
            "thur": "",
            "score": "",
            "round": ""
       },
        {
            "pos": "2",
            "person": "John",
            "thur": "",
            "score": "16",
            "round": "3"
       },
       {
            "pos": "3",
            "person": "Peter Lynch",
            "thur": "",
            "score": "5",
            "round": "2"
       }
    ],
    "tour": "Camping",
    "date": "Thursday Jul 23 - Sunday Jul 26, 2015"
  }

解析JSON pos数组的代码：

 // ALL JSON nodes
private static final String TAG_MESSAGES = "pos";
private static final String TAG_ID = "pos";
private static final String TAG_FROM = "person";
private static final String TAG_EMAIL = "thur";
private static final String TAG_SUBJECT = "round";
private static final String TAG_DATE = "score";


// These are outside of array pos    
private static final String TAG_TOUR = "tour";
private static final String TAG_TOURDATE = "date";



 try {
            inbox = json.getJSONArray(TAG_MESSAGES);

            inbox.toString();


            // looping through All messages
            for (int i = 0; i < inbox.length(); i++) {
                JSONObject c = inbox.getJSONObject(i);

                // Storing each json item in variable
                String id = c.getString(TAG_ID);
                // creating new HashMap
                HashMap<String, String> map = new HashMap<String,    String>();

                // adding each child node to HashMap key => value
                map.put(TAG_ID, id);
                map.put(TAG_FROM, from);
                map.put(TAG_EMAIL, mailer);
                map.put(TAG_DATE, date);
                map.put(TAG_SUBJECT, subject);

                // adding HashList to ArrayList
                inboxList.add(map);

Answer 1

因为你可以从你的json获得JSONArray，你也可以从中获得String。

类似的东西：

json.getString("tour");
json.getString("date");

Answer 2

试试这个，

String tour = "", date = "";

try {
if(json.has("tour"))
            tour= json.getString("tour");
if(json.has("date"))
            date= json.getString("date");

} Catch(Exception e) {
}

即使没有日期/旅游密钥（如果缺少），也不会崩溃

Answer 3

        inbox = json.getJSONArray(TAG_MESSAGES);
        String tour=json.getString("tour");
        String date=json.getString("date");

如何在Array之外提取JSON值

3 个答案: