Question

我试图通过$ .get（）从php文件中获取URL值，这里是代码：

PHP文件夹名为＆＃39; jquery_con4.php＆＃39;：

echo (isset($_GET['req'])) ? 'found':'notfound';

JQuery调用了＃pass; js＆＃39;：

$.get('connection/jquery_con4.php', function(data){
        alert(data);
});

名为＆＃39; password_c.php＆＃39;的主文件夹其中包括名为＆＃39; pass.js＆＃39;的javascript。它有$ .get但是它显示了我的注释＆＃39; notfound＆＃39;，＆amp;如果删除了echo，则显示为＆＃39; undefined index：req＆＃39; ---网址是：＆＃39; http://localhost/series/skyface/password_c.php?req=65yDq0zI39UcRSF＆＃39;

谢谢！

Answer 1

http://localhost:8888/series/skyface/password_c.php?req=65yDq0zI39UcRSF

为了将URL查询字符串中的'req'值传递给jquery_con4.php脚本，您需要一个JS函数来为您抓取它并将其传递给ajax请求。

下面是一个如何运作的例子。

/series/skyface/password_c.php

switch CLLocationManager.authorizationStatus() {
    case .AuthorizedWhenInUse, .Restricted, .Denied:
        let alertController = UIAlertController(
            title: "Background Location Access Disabled",
            message: "In order to be notified, please open this app's settings and set location access to 'Always'.",
            preferredStyle: .Alert)

        let cancelAction = UIAlertAction(title: "Cancel", style: .Cancel, handler: nil)
        alertController.addAction(cancelAction)

        let openAction = UIAlertAction(title: "Open Settings", style: .Default) { (action) in
            if let url = NSURL(string:UIApplicationOpenSettingsURLString) {
                UIApplication.sharedApplication().openURL(url)
            }
        }
        alertController.addAction(openAction)

        self.presentViewController(alertController, animated: true, completion: nil)
}

/main.js：

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <title>Document</title>
</head>
<body>
  <script src="http://code.jquery.com/jquery-1.11.3.min.js"></script>
  <script src="../../main.js"></script>
</body>
</html>

/connection/jquery_con4.php：

jQuery(document).ready(function($) {

  function getParameterByName(name) {
    name = name.replace(/[\[]/, "\\[").replace(/[\]]/, "\\]");
    var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
        results = regex.exec(location.search);
    return results === null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));
  }

  function success(data) {
    console.log(data);
  }


  $.ajax({
    url: '/connection/jquery_con4.php',
    data: {req : getParameterByName('req')},
    success: success
  });

});

$ .get（）不工作Jquery

1 个答案: