Question

我想通过GWT上传上传更大的文件（6 MB）。默认情况下，它仅允许最大大小为~3 MB的文件。因此，我使用以下上下文调整了我的web.xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
    <context-param>
        <param-name>maxSize</param-name>
        <param-value>102400000</param-value>
    </context-param>


    <context-param>
        <!-- max size of any uploaded file -->
        <param-name>maxFileSize</param-name>
        <param-value>102400000</param-value>
    </context-param>

但是我收到以下错误：

2015-07-23 22:26:05 ERROR UploadServlet:70 - UPLOAD-SERVLET (0d0quwXW6dcRxDl_G4ZHag) getUploadStatus: GWTU-019405167154036462 finished with error: The request was rejected because its size: 6.054 KB, exceeds the maximum: 3.071 KB

我的代码在app引擎上运行，我的上传操作扩展了AppEngineUploadAction

public class MyUploadAction extends AppEngineUploadAction

在我的上传操作中，我甚至覆盖了方法＆＃34; checkRequest＆＃34;什么都不做，但它没有任何帮助

@Override
public void checkRequest(HttpServletRequest request) {
    logger.info("Skip all checks completly");
}

我做错了什么？如何通过GWT上传启用我的应用程序以获取更大的文件？

Answer 1

刚刚检查过，对我来说 - 更改此参数可以正常工作：

<context-param>
    <!-- max size of the upload request -->
    <param-name>maxSize</param-name>
    <param-value>9145728</param-value>
</context-param>

GWTUpload - 最大文件大小上下文参数无效

1 个答案: