Question

我的回复应来自 MailChimp webhook网址。

这是行BODY：

$DB_struct | Where-Object { $_.bundle -eq 'DESKTOP A' } | Select-Object -ExpandProperty app

我之前在使用Spring Controllers时曾使用RAW BODY type=usub&fired_at=2015-07-23+17%3A19%3A34&data%5Baction%5D=unsub&data%5Breason%5D=manual&data%5Bid%5D=9383uy636&data%5Bemail%5D=youremail%40YOURDOMAIN.com&data%5Bemail_type%5D=html&data%5Bip_opt%5D=202.9.3.003&data%5Bweb_id%5D=404004&data%5Bmerges%5D%5BEMAIL%5D=YOUREMAIL%40YOURDOMAIN.com&data%5Bmerges%5D%5BFNAME%5D=NAME&data%5Bmerges%5D%5BLNAME%5D=LASTNAME&data%5Blist_id%5D=2288883 FORM/POST PARAMETERS fired_at: 2015-07-22 12:19:34 data[email]: YOUREMAIL@DOMAINNAME.com data[id]: 56775409ta data[web_id]: 09833944 data[merges][EMAIL]: YOUREMAIL@DOMAINNAME.com type: unsub data[list_id]: 99884hy372 data[merges][FNAME]: Name data[ip_opt]: 202.0.9.3333 data[reason]: manual data[email_type]: html data[action]: unsub data[merges][LNAME]: LastName **QUERYSTRING key: a4483983hu473004884j0x** HEADERS Accept: */* Total-Route-Time: 0 Host: requestb.in Connection: close Content-Length: 395 User-Agent: MailChimp.com Connect-Time: 0 Via: 1.1 vegur X-Request-Id: 6633d8-653e-4cea-884j-9933ju4773h Content-Type: application/x-www-form-urlencoded，但我不知道如何从上面的响应中获取数据，例如数据[merges] [FNAME] ：< / p>

如何在Spring控制器中获取QueryString？ QUERYSTRING键：a4483983hu473004884j0x

@RequestParameter

感谢您的帮助！

Answer 1

您只需将WebRequest作为参数注入控制器POST方法，然后使用Mailchimp webhook中的给定参数请求getParameter（）。

例如：

@RequestMapping(path="/MyUrl", method=RequestMethod.POST)
public ModelAndView process(WebRequest request){
    System.out.println(request.getParameter("type"));
    System.out.println(request.getParameter("data[merges][EMAIL]"));
    return new ModelAndView([YOURVIEWHERE]);
}

全部......

问候。

如何在Spring Controller中检索FORM / POST参数？

1 个答案: