Question

我尝试将少量文件转换为css文件，然后将其他css文件合并在一起组成一个css文件。我没有收到任何错误，但从未创建过css文件。有没有办法将两组不同的css组合在一起形成一个css文件？提前谢谢。

var gulp = require("gulp");
var gulpUtil = require("gulp-util");
var concat = require("gulp-concat");
var uglify = require("gulp-uglify");
var rename = require("gulp-rename");
var less = require("gulp-less");
var minify = require("gulp-minify-css");
var notify = require("gulp-notify");
var addsrc = require("gulp-add-src");

/*CSS Section*/
gulp.task("build-less", function () {

    return gulp.src([
            "Less/common.less",
            "Less/box.less",
            "Less/callout.less",
            "Less/form-controls.less",
            "Less/form.less",
            "Less/scrollbar.less",
            "Less/overflow-table.less",
            "Less/button.less",
            "Less/theme.less",
            "Less/auto-complete.less"
        ]).pipe(less())
        .pipe(addsrc([
            "Css/bootstrap.css",
                "Css/bootstrap-theme.css",
                "Distribution/Styles/theme.css",
                "Css/font-awesome.css",
                "Css/font-awesome-animation.css",
                "Css/animate.css",
                "Css/bootstrap-select.css"
        ]))
        .pipe(concat("dustball.min.css"))
        .pipe(minify())
        .pipe(gulp.dest("Destination/Styles"));
});

Answer 1

刚刚遇到一个插件调用merge2，它工作。以下是更新版本。

for cell in sheet.col(1): 
    if cell.value == item:
        print "Data: ",cell

gulpjs合并css而不是

1 个答案: