Question

我有一个POJO，看起来像这样：

public class Thing
{
   private final int x;
   private final int y;
   private final int z;

   public Thing(String strThing)
   {
       // parse strThing which is in some arbitrary format to set x, y and z
   }

   @Override
   public String toString()
   {
       // return a string representation of thing
       // (same format as that parsed by the constructor)
   }

   @Override
   public boolean equals(Object obj) ...

   @Override
   public int hashCode() ...

}

我希望将它用作映射的键（例如HashMap<Thing, SomeOtherPOJO>），当序列化为json时，使用Thing的toString（）表示键，并且在反序列化时使用String构造函数。这可能是使用像jackson数据绑定注释这样简单的东西吗？解决这个问题的最佳方法是什么？

Answer 1

通过实验（我认为文档本来可以更加清楚）我发现我可以在JsonCreator构造函数上使用String注释，在JsonValue上使用toString() {1}}实现我想要的方法：

public class Thing
{
   private final int x;
   private final int y;
   private final int z;

   @JsonCreator
   public Thing(String strThing)
   {
       // parse strThing which is in some arbitrary format to set x, y and z
   }

   @Override
   @JsonValue
   public String toString()
   {
       // return a string representation of thing
       // (same format as that parsed by the constructor)
   }

   @Override
   public boolean equals(Object obj) ...

   @Override
   public int hashCode() ...

}

Answer 2

你可以创建一个扩展JsonSerializer的新类并覆盖它的serialize方法。将您想要在toString（）方法中编写的实现写入JsonGenerator的writeString（）方法，如图所示。您将不得不在项目中使用jackson-core-asl.jar和jackson-mapper-asl.jar。下面是JsonThingSerializer.java类

import java.io.IOException;
import org.codehaus.jackson.JsonGenerator;
import org.codehaus.jackson.JsonProcessingException;
import org.codehaus.jackson.map.JsonSerializer;
import org.codehaus.jackson.map.SerializerProvider;


public class JsonThingSerializer extends JsonSerializer<Thing>{ //note use of generics

@Override
public void serialize(Thing myThing, JsonGenerator gen,
        SerializerProvider provider) throws IOException,
        JsonProcessingException {

    gen.writeString("I want this way.. which I was thinking to implement inside toString() method "+" "+myThing.getX()+" "+myThing.getY()+" "+myThing.getZ());
}

}

在Thing.java中使用以下注释

import org.codehaus.jackson.annotate.JsonAutoDetect;
import org.codehaus.jackson.map.annotate.JsonSerialize;

@JsonAutoDetect
@JsonSerialize(using=JsonThingSerializer.class)
public class Thing
{
   private final int x;
   private final int y;
   private final int z;

   public Thing(String strThing)
   {
       // parse strThing which is in some arbitrary format to set x, y and z
       //insert your own implementation to get x, y and z
       x=y=z=10;
   }

   @Override
   public String toString()
   {
       //no need to override this for json serialization.. mapper will not use it
   }

   @Override
   public boolean equals(Object obj){
     //you can have your own implementation
   }

   @Override
   public int hashCode() {
     //you can have your own implementation
    }

public int getX() {
    return x;
}

public int getY() {
    return y;
}

public int getZ() {
    return z;
}

}

您可以使用以下代码测试您的代码。

import java.io.IOException;
import org.codehaus.jackson.JsonGenerationException;
import org.codehaus.jackson.map.JsonMappingException;
import org.codehaus.jackson.map.ObjectMapper;

public class TestJsonSerialization {

    public static void main(String[] args) {

        Thing thing =new Thing("your strThing which is in some arbitrary format to set x, y and z");
        ObjectMapper mapper =new ObjectMapper();
        try {
            String thingString = mapper.writeValueAsString(thing);
            System.out.println(thingString);
        } catch (JsonGenerationException e) {
            e.printStackTrace();
        } catch (JsonMappingException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }

}

Blow是输出：

＆＃34;我想这样..我想在toString（）方法中实现10 10 10＆＃34;

使用toString进行rapidxml序列化并使用String构造函数进行反序列化

2 个答案: