Question

如何使用preg_replace剥离与父标记相同的标记？例如，我有一个名为<strip>的标签，我想剥离任何<strip>的子标签 <strip><strip>Avoid my tag</strip></strip>我想要那样 - ＆gt; <strip>Avoid my tag</strip>我不太了解preg_ *，但那就是我已经拥有的东西：

preg_replace_callback(
  '#\<strip\>(.+?)\<\/strip\>#s',
  create_function(
    '$matches',
    'return "<strip>".htmlentities($matches[1])."</strip>";'
  ),
  $content
);

这个小函数会对<strip>个标记内的所有内容应用htmlentities，而idon不希望<strip>标记在彼此内部重复

感谢

Answer 1

请不要使用html dom的正则表达式，看看DOMXPath该文档是HERE

这里有一个例子：

$doc = new DOMDocument();
$doc->loadHTMLFile($file);
$xpath = new DOMXpath($doc);
$elements = $xpath->query("/html/body/*");
foreach ($elements as $element) {
    $nodes = $element->childNodes;
    foreach ($nodes as $node) {
      //Do your stuff here :) 
      echo $node->nodeValue. "\n";
    }
}

如果是某些XML，请查看SimpleXMLElement HERE

Answer 2

如果您想要正则表达式，请执行此操作

$str = 'abc<strip><strip><strip>Avoid my tag</strip></strip></strip>def';
echo preg_replace('
     /((<strip>(?=<strip>))*)(<strip>[^<]+<\/strip>)(((?<=<\/strip>)<\/strip>)*)/',
     '\3', $str); // abc<strip>Avoid my tag</strip>def

Demo and explanation

更新再一步

echo preg_replace_callback(
  '/((<strip>(?=<strip>))*)<strip>([^<]+)<\/strip>(((?<=<\/strip>)<\/strip>)*)/',
  create_function(
    '$matches',
    'return "<strip>".htmlentities($matches[3])."</strip>";'
  ),
  $content
);

php - 剥离与父标记相同的标记

2 个答案: