Question

我是Spring新手，我需要从spring控制器传递一个XML文件到我的JavaScript文件。任何人都可以详细说明我应该怎么做吗？ 我在我的控制器上尝试了这个，但响应主体不是内容。

@Api(value = "XML", description = "")
@RequestMapping("/XML/v1/setting")
public class XMLController{

    @RequestMapping(method = RequestMethod.GET,
         value = "/createFOO",
         produces = "application/xml")
    @ResponseStatus(HttpStatus.CREATED)
    @ResponseBody
    public Document createFOO(){
       DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
       DocumentBuilder builder;
       Document doc1 = null;
       try {
          builder = factory.newDocumentBuilder();
           doc1 = builder.parse(new FileInputStream("largeXmlGraph.xml"));
       } catch (ParserConfigurationException | SAXException | IOException e) {
                e.printStackTrace();
       }
       return doc1;
    }
}

Answer 1

你正在走向复杂的道路。

@RequestMapping(method = RequestMethod.GET,value = "/createFOO",produces = "application/xml")
public void createFOO(OutputStream out){
    try (InputStream is = new FileInputStream("largeXmlGraph.xml")) {
        StreamUtils.copy(is, out);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

这样的东西应该有用，你可能想要添加更好的异常处理（例如向客户端发送错误）。

Answer 2

为了使用application/xml，请添加此依赖项

<dependency>
    <groupId>com.fasterxml.jackson.dataformat</groupId>
    <artifactId>jackson-dataformat-xml</artifactId>
</dependency>

到Multiple scenarios @RequestMapping produces JSON/XML together with Accept or ResponseEntity的参考链接

从spring MVC Controller

2 个答案: