Question

我有这个SQL查询，当它运行到phpMyAdmin时它正常工作。

SELECT COUNT( * ) , LENGTH( Number ) AS Numbers
FROM  `history_2015-07-22` 
WHERE Number NOT LIKE  '123%'
OR LENGTH( Number ) <50
GROUP BY Numbers
ORDER BY TIME =  '2015-07-22 00:00:01' ASC

我现在想制作一个简单的php页面，我想在浏览器上显示查询结果，但我无法弄清楚如何完全回显它。所以我做到了这一点：

$result = $pdo->prepare("SELECT COUNT( * ) , LENGTH( Number ) AS Numbers
                         FROM  `history_2015-07-22` 
                         WHERE Number NOT LIKE  '123%'
                         OR LENGTH( Number ) <50
                         GROUP BY Numbers
                         ORDER BY TIME =  '2015-07-22 00:00:01' ASC ");
$result->execute();
foreach ($result as $Numbers)
{
    echo '<div class="container">
                '.$Numbers['COUNT(*)'].'
                '.$Numbers['LENGTH(Number)'].'
          </div>';
}

我想要回应的是Count和Length。我确信这是一件非常简单的事情，但我无法弄明白。

Answer 1

首先，您能否解释一下您正在尝试使用SQL查询做什么？

根据我的理解，你可以试试这个：

$result = $pdo->prepare("SELECT COUNT( * ) AS ct_all, LENGTH( `Number` ) AS Numbers
                         FROM  `history_2015-07-22` 
                         WHERE `Number` NOT LIKE ('123%')
                         AND Numbers < 50
                         GROUP BY Numbers
                         ORDER BY `TIME` ASC");
$result->execute();
$results = $result->fetchAll();
foreach ($results as $row) {
    echo '<div class="container">';
    echo $row['ct_all'] . ' // ';
    echo $row['Numbers'];
    echo '</div>';
}

Answer 2

$result = $pdo->prepare("SELECT COUNT( * ) as cnts, LENGTH( Number ) AS num
                         FROM  `history_2015-07-22` 
                         WHERE Number NOT LIKE  '123%'
                         OR LENGTH( Number ) <50
                         GROUP BY num
                         ORDER BY TIME =  '2015-07-22 00:00:01' ASC ");
$result->execute();
foreach ($result as $Numbers)
{
    echo '<div class="container">
                '.$Numbers['cnts'].'
                '.$Numbers['num'].'
          </div>';
}

Answer 3

在这里看看我已经指出了一些问题。

$result = $pdo->prepare("SELECT COUNT( * ) AS ct_all, LENGTH( `Number` ) AS Numbers
                         FROM  `history_2015-07-22` 
                         WHERE `Number` NOT LIKE ('123%')
                         AND Numbers < 50
                         GROUP BY Numbers
                         ORDER BY `TIME` ASC");
    $result->execute();
   // the problem is.. 
   // you are trying to fetch $result but here $result is just executing 
   // you cannot retrive anything unless you didn't declare it 
   /*  here $result has nothing in it; is just executed first
    * declare it 
   */
     $result = $result->execute();
    /* Then Fetch it 
    And then You Can Use You Fetch Var with index to retrive data. 
    e.g */
    $allData = $result->fetchAll();
    foreach ($allData as $SingleData)
{
// here you must place indexes of your Query 
// e.g $SingleData['id'] or $SingleData[0]
        echo '<div class="container">
                    '.$SingleData['COUNT(*)'].'
                    '.$SingleData['LENGTH(Number)'].'
              </div>';
    }

从数据库中选择count（*）

3 个答案: