Question

好吧，我坚持这个：

Code_User    Code_Concept    Concept                 Quantity     Amount      Total_Amount
12           1               1/2 DIETA               2.000        24.000      24.000
12           10              APARCAMIENTO            2.000        0           0
12           8               COMUNICACIONES          2.000        0           0
12           3               DIETA COMPLETA          2.000        160.000     160.000
12           2               KILOMETRAJE             6.000        160         480
12           17              LOCOMOC. SEDE           2.000        0           0
12           9               MATERIAL DE OFICINA     2.000        0           0
12           7               PEAJES                  2.000        0           0
12           18              VARIOS SUPL. DIVERSOS   2.000        0           0
12           NULL            NULL                    22.000       184.160     184.480

1505         1               1/2 DIETA               10.000       120.000     120.000
1505         10              APARCAMIENTO            22.000       55.380      55.380
1505         2               KILOMETRAJE             12.478.000   3.360       998.240
1505         17              LOCOMOC. SEDE           0            10.000      0
1505         7               PEAJES                  26.000       242.300     242.300
1505         18              VARIOS SUPL. DIVERSOS   2.000        47.900      6.600
1505         NULL            NULL                    12.538.000   478.940     1.422.520

2816         10              APARCAMIENTO            1.000        1.000       1.000
2816         3               DIETA COMPLETA          2.000        160.000     160.000
2816         2               KILOMETRAJE             893.000      560         71.440
2816         17              LOCOMOC. SEDE           3.000        33.000      33.000
2816         18              VARIOS SUPL. DIVERSOS   3.000        4.680       4.680
2816         NULL            NULL                    902.000      199.240     270.120

我必须为用户1505显示概念：3,8和9（缺少概念），数字为0.用户2816错过概念1,9,8 .. 如何通过Code_User包含所有缺少的概念？我使用此查询得到了这个结果：

SELECT --eh.Ex_Guid
eh.Code_User
,ISNULL(el.Code_Concept,'9999999999') AS Code_Concept
,CASE WHEN el.Code_Concept IS NULL THEN 'ZZZZZZZZZZ' ELSE MAX(ec.Description) END AS Concept
,SUM(el.Quantity) AS Quantity
,SUM(el.Amount) AS Amount
,SUM(el.Total_Amount) AS Total_Amount
FROM expenses_head AS eh
INNER JOIN expenses_lines AS el
ON eh.Ex_Guid = el.Ex_Guid
INNER JOIN 
(
    -- jerarquia de usuarios y tipo
    SELECT DISTINCT CONVERT(VARCHAR,vhuos.Code_Seller) AS Code_User 
    ,pu.Code_Type
    FROM view_hier_user_organ_seller AS vhuos
    INNER JOIN prj_users AS pu
    ON pu.Code_User = CONVERT(VARCHAR,vhuos.Code_Seller)
    WHERE 1=1
    AND vhuos.Code_Sales_Org='1010' --FILTRO OBLIGATORIO
    AND vhuos.Code_User='10'--USUARIO EN SESION
    -- AND Code_User IN (...) -- usuarios multiselect
)AS u
ON eh.Code_User = u.Code_User
RIGHT JOIN 
(
    -- conceptos por tipo de usuario
    SELECT DISTINCT ec.Code_Concept,ec.Description,eo.Code_Type_User
    FROM expenses_concepts AS ec
    INNER JOIN expenses_organization AS eo
    ON ec.Code_Concept = eo.Code_Concept
--ORDER BY Code_Type_User,Description
)AS ec
ON el.Code_Concept = ec.Code_Concept
AND ec.Code_Type_User = u.Code_Type
WHERE 1=1
AND eh.Delete_Date IS NULL 
AND el.Delete_Date IS NULL
AND el.Date_Expenses>'20150215' --filtro fecha inicio
AND el.Date_Expenses<'20150510' --filtro fecha fin
GROUP BY eh.Code_User,ROLLUP(el.Code_Concept)
ORDER BY eh.Code_User,Concept,el.Code_Concept

Answer 1

如果以下查询有效，请告诉我：

select abc.code_user,
abc.code_concept,
sam.concept,
sam.Quantity,
sam.amount,
sam.total_amount
from 
(
select distinct code_user,t.code_concept
from sam as a
cross apply(select distinct code_concept from sam) as t(code_concept)
) as abc
left join sam 
on abc.code_user = sam.code_user and isnull(abc.code_concept,'') = isnull(sam.code_concept,'')

上述查询将包含所有缺少的code_concept。您可以将此输出存储在临时表中。截断表并将临时表中的记录插入表中。

Answer 2

首先，谢谢你的答复。我终于使用混合php和我的第一个查询解决了这个问题。在此解决方案之前，我尝试过交叉连接，但它没有起作用，导致结果数量。小记录工作得很好。截断不是一种选择。如果多个用户想要使用相同的报表，则并发将保留最新用户的结果。

SQL Server - 按组添加缺失的行（费用概念）

2 个答案: