如何只提取mysql和php中具有非零值的列？

时间：2015-07-17 11:33:33

标签： php html mysql

我试图在网页上提取和显示，只有mysql数据库中的非零列。哪个列的日期是0000-00-00，我不想在网页上显示那些列 下面分别是HTML代码和php脚本

<form action="search.php" method="post">
<p>
<lable>ENTER SO NUMBER</lable>
<input type="text"  name="soid" id="soid" >
</p>
<p><button><img src="http://icons.iconarchive.com/icons/harwen/pleasant/256/Search-icon.png"  height="50" />SEARCH</button></p>
</form>
</html>

PHP脚本，

<?php

$userinput1 = $_POST['soid'];

$servername = "localhost";
$username = "root";
    $password = "";
    $dbname = "status";

$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_errno) {
    printf("Connect failed: %s\n", $conn->connect_error);
    exit();
   }

$result = mysqli_query($conn, "SELECT * FROM $dbname.statusinfo WHERE soid = '$userinput1'  ") or die(mysqli_error
        ($conn));
echo "<p><font size= 4>SO_NUMBER:$userinput1";

echo "<table border='1'>
<tr>
<style>
th{
color: blue;
}

td{
color: black;
}
</style>

<th>Sample Recived</th>
<th>Mol-Bio Extraction</th>
<th>Extraction QC</th>
<th>Library Prep</th>
<th>Library QC</th>
<th>Sequencing</th>
<th>Data Check</th>
<th>RE Sequencing</th>
<th>QC Check</th>
<th>Analysis Started</th>
<th>Analysis Completed</th>
<th>Report</th>
<th>Outbound</th>
 </tr>";
while($row = mysqli_fetch_assoc($result))
   {
   echo "<tr>";
       echo "<br />";
    echo "Department:".$row['dept'] ;
    echo "<td>" . $row['samplerecived'] . "</td>";
       echo "<td>" . $row['molbioextraction'] . "</td>";
    echo "<td>" . $row['molbioextractionqc'] . "</td>";
    echo "<td>" . $row['libraryprep'] . "</td>";
       echo "<td>" . $row['libraryqc'] . "</td>";
    echo "<td>" . $row['sequencing'] . "</td>";
    echo "<td>" . $row['datacheck'] . "</td>";
       echo "<td>" . $row['resequencing'] . "</td>";
    echo "<td>" . $row['qccheck'] . "</td>";
    echo "<td>" . $row['analysisstarted'] . "</td>";
       echo "<td>" . $row['analysiscompleted'] . "</td>";
    echo "<td>" . $row['report'] . "</td>";
    echo "<td>" . $row['outbound'] . "</td>";
echo "</tr>";
   }
   echo "</table>";  
?>

现在我正在网页上显示所有列，我只需要那些日期记录未记录的栏目列 这是mysql表。 enter image description here
 我得到的输出是
enter image description here
我想只显示非零列。 提前致谢

2 个答案:

答案 0 :(得分：3)

试试这个：

$result = mysqli_query($conn, "SELECT * FROM $dbname.statusinfo WHERE soid = '$userinput1' AND date_column <> '0000-00-00' ") or die(mysqli_error($conn));

虽然使用mysql，你甚至可以这样做：

$result = mysqli_query($conn, "SELECT * FROM $dbname.statusinfo WHERE soid = '$userinput1' AND date_column > '0000-00-00' ") or die(mysqli_error($conn));

希望这有帮助

修改

我现在可以看到你想修改问题:) 不幸的是，我不知道如何使用SQL（有人可能）。

您正在输出列标题，因此不输出特定列会导致它们出现在错误的列中，因此您只需输出任何时间是什么

这就是我在PHP中的方式。 （如果我再次错过了你的观点，我可能会自己开枪：））

<?php
    $userinput1 = $_POST['soid'];

    $servername = "localhost";
    $username   = "root";
    $password   = "";
    $dbname     = "status";

    $conn = new mysqli($servername, $username, $password, $dbname);
    if ($conn->connect_errno) {
        printf("Connect failed: %s\n", $conn->connect_error);
        exit();
    }

    $result = mysqli_query($conn, "SELECT * FROM $dbname.statusinfo WHERE soid = '$userinput1'  ") or die(mysqli_error($conn));

    $arrayHeadings = array(
        "dept"                  => "Department", 
        "samplerecived"         => "Sample Recived",
        "molbioextraction"      => "Mol-Bio Extraction",
        "molbioextractionqc"    => "Extraction QC",
        "libraryprep"           => "Library Prep",
        "libraryqc"             => "Library QC",
        "sequencing"            => "Sequencing",
        "datacheck"             => "Data Check",
        "resequencing"          => "RE Sequencing",
        "qccheck"               => "QC Check",
        "analysisstarted"       => "Analysis Started",
        "analysiscompleted"     => "Analysis Completed",
        "report"                => "Report",
        "outbound"              => "Outbound",
    );

?>
<style>
    th{
        color: blue;
    }

    td{
        color: black;
    }
</style>

<table border='1'>
    <tr>
        <?php foreach($arrayHeadings as $key => $name): ?>
            <th><?= $name; ?></th>
        <?php endforeach; ?>
    </tr>
    <tr>
        <?php while($row = mysqli_fetch_assoc($result)): ?>
            <?php foreach($arrayHeadings as $key => $name): ?>
                <?php if($row[$key] != "0000-00-00"): ?>
                    <td><?= $row[$key]; ?></td>
                <?php else: ?>
                    <td></td>
                <?php endif; ?>
            <?php endforeach; ?>
        <?php endwhile; ?>
    </tr>
</table>

修改

如果字段包含0000-00-00，则不输出表格标题。 这依赖于一次只输出一个元素。

<?php
    $userinput1 = $_POST['soid'];

    $servername = "localhost";
    $username   = "root";
    $password   = "";
    $dbname     = "status";

    $conn = new mysqli($servername, $username, $password, $dbname);
    if ($conn->connect_errno) {
        printf("Connect failed: %s\n", $conn->connect_error);
        exit();
    }

    $result = mysqli_query($conn, "SELECT * FROM $dbname.statusinfo WHERE soid = '$userinput1'  ") or die(mysqli_error($conn));

    $arrayHeadings = array(
        "dept"                  => "Department", 
        "samplerecived"         => "Sample Recived",
        "molbioextraction"      => "Mol-Bio Extraction",
        "molbioextractionqc"    => "Extraction QC",
        "libraryprep"           => "Library Prep",
        "libraryqc"             => "Library QC",
        "sequencing"            => "Sequencing",
        "datacheck"             => "Data Check",
        "resequencing"          => "RE Sequencing",
        "qccheck"               => "QC Check",
        "analysisstarted"       => "Analysis Started",
        "analysiscompleted"     => "Analysis Completed",
        "report"                => "Report",
        "outbound"              => "Outbound",
    );

?>
<style>
    th{
        color: blue;
    }

    td{
        color: black;
    }
</style>

<table border='1'>
    <tr>
        <?php foreach($arrayHeadings as $key => $name): ?>
            <?php if($row[$key] != "0000-00-00"): ?>
                <th><?= $name; ?></th>
            <?php endif; ?>
        <?php endforeach; ?>
    </tr>
    <tr>
        <?php while($row = mysqli_fetch_assoc($result)): ?>
            <?php foreach($arrayHeadings as $key => $name): ?>
                <?php if($row[$key] != "0000-00-00"): ?>
                    <td><?= $row[$key]; ?></td>
                <?php endif; ?>
            <?php endforeach; ?>
        <?php endwhile; ?>
    </tr>
</table>

答案 1 :(得分：0)

像这样编辑您的查询：

$result = mysqli_query($conn, "SELECT * FROM $dbname.statusinfo WHERE soid = '$userinput1' AND date IS NOT NULL  ") or die(mysqli_error($conn));

在日期字段

之后添加“IS NOT NULL”
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