Question

我正在使用Python Webdriver。我在点击“添加”按钮时遇到问题。我正在使用Webdriver Wait，当我运行我的代码时出现以下错误。

Traceback (most recent call last):
File "C:\Webdriver\ClearCore 501\TestCases\AdministrationPage_TestCase.py", line 164, in test_add_Project
administration_page.add_project(project_name)
File "C:\Webdriver\ClearCore 501\Pages\admin.py", line 63, in add_project
element = wait.until(EC.element_to_be_clickable(By.XPATH, '//span[@class="gwt-InlineLabel" and contains(text(), "Projects")]/following-sibling::*/div[@class="gwt-HTML" and contains(text(), "Add...")]'))
TypeError: __init__() takes exactly 2 arguments (3 given)

我的网络驱动程序代码是

wait = WebDriverWait(self.driver, 60)
element = wait.until(EC.element_to_be_clickable(By.XPATH, '//span[@class="gwt-InlineLabel" and contains(text(), "Projects")]/following-sibling::*/div[@class="gwt-HTML" and contains(text(), "Add...")]'))
element.click()

我做错了什么？ Xpath是有效的，因为我在Firefox，Firepath中检查过它。它找到了按钮。

Answer 1

您必须将定位器括在元组中：

element = wait.until(EC.element_to_be_clickable((By.XPATH, '//span[@class="gwt-InlineLabel" and contains(text(), "Projects")]/following-sibling::*/div[@class="gwt-HTML" and contains(text(), "Add...")]')))

Python Selenium Webdriver Wait.Until显示错误需要2个参数3

1 个答案: