Question

我正在尝试获取过去30天的综合浏览量。和浏览量总计。但出于某种原因，我得到了两者相同的价值。因此，它将价值观合并在一起。

SELECT p.ID, 
       p.post_title post_title,
       p.post_date post_date, 
       SUM(gvd.unique_pageviews) total_unique_pageviews, 
       SUM(gvd.pageviews) total_pageviews,
       thirty_days_views.unique_pageviews thirty_days_views_unique_pageviews,
       thirty_days_views.pageviews thirty_days_views_pageviews
FROM wp_posts as p
INNER JOIN wp_postmeta as pm on pm.post_id = p.ID
LEFT JOIN wp_google_views_daily gvd ON gvd.post_id = p.ID
LEFT JOIN (
           SELECT p.ID,
                  SUM(gvd.unique_pageviews) unique_pageviews,
                  SUM(gvd.pageviews) pageviews
           FROM wp_posts p
           INNER JOIN wp_postmeta as pm on pm.post_id = p.ID
           LEFT JOIN wp_google_views_daily gvd ON gvd.post_id = p.ID
           WHERE
                pm.meta_key = 'template_style'
           AND  pm.meta_value = 'list'
           AND  p.post_status = 'publish'
           AND  p.post_password = ''
           AND  p.post_date >= DATE(DATE_SUB(NOW(), INTERVAL 30 day))
                                GROUP BY p.ID
                                ORDER BY p.post_date DESC
          ) thirty_days_views ON thirty_days_views.ID = p.ID
WHERE
    pm.meta_key = 'template_style'
AND pm.meta_value = 'list'
AND p.post_status = 'publish'
AND p.post_password = ''
GROUP BY 
    p.ID
ORDER BY 
    p.post_date DESC

如何获取不受其他子查询影响的值？这样我可以获得过去30天的总浏览量和综合浏览量？

Answer 1

我工作的人帮助了我。这是解决方案：

SELECT
    p.ID, 
    p.post_title post_title,
    p.post_date post_date, 
    all_days_views.unique_pageviews total_unique_pageviews,
    all_days_views.pageviews total_pageviews,
    thirty_days_views.unique_pageviews thirty_days_views_unique_pageviews,
    thirty_days_views.pageviews thirty_days_views_pageviews
FROM 
    wp_posts as p
    INNER JOIN wp_postmeta as pm on pm.post_id = p.ID and pm.meta_key = 'template_style' and pm.meta_value = 'list'
    LEFT JOIN (
        SELECT 
            post_id,
            SUM(unique_pageviews) unique_pageviews,
            SUM(pageviews) pageviews
        FROM 
            wp_google_views_daily
        GROUP BY post_id
    ) all_days_views ON all_days_views.post_id = p.ID
    LEFT JOIN (
        SELECT 
            post_id,
            SUM(unique_pageviews) unique_pageviews,
            SUM(pageviews) pageviews
        FROM 
            wp_google_views_daily
        WHERE
            date >= DATE(DATE_SUB(NOW(), INTERVAL 30 day))
        GROUP BY post_id
    ) thirty_days_views ON thirty_days_views.post_id = p.ID
WHERE
    p.post_status = 'publish' AND
    p.post_password = ''
ORDER BY p.post_date DESC

使用MySQL无法从子查询中获得分离的值

1 个答案: