Question

我正在使用mySound播放声音，具体取决于是否满足某个条件。即使条件不满足，我也会遇到声音相互影响的问题。这是我的代码有什么想法吗？

Game.countAnimals = function(playerGo) {
  var count = {bulls:0, cows:0};
  Game.counter = 1;
  for (var i = 0; i < playerGo.length; i++) {
    var digPresent = playerGo.indexOf(Game.score[i]);
    if (playerGo[i] == Game.score[i]) {
      count.bulls++;
    }
    else if (digPresent>=0) {
      count.cows++;
    }
    Game.counter++
    if (count.bulls === playerGo.length && Game.counter < 7){
      mySound2 = new Audio("sounds/Freedom%20Tastes%20Good.mp3");
      mySound2.play(); 
    }
    else if (count.bulls !== playerGo.length && Game.counter < 7) {
      mySound1 = new Audio("sounds/Ass%20is%20dead.mp3");
      mySound1.play();
    }
    else if (Game.counter > 7 ){
      mySound = new Audio("sounds/Kill%20You%20Dog.mp3");
      mySound.play(); 
    }

Answer 1

在播放新声音之前，您应该停止所有其他声音。此外，在需要时，不要在函数中实例化声音 - 您只有三个声音，因此在页面加载时，在函数外部实例化它们。

所以固定的代码片应该是这样的：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct data{
    int testone;
    int testtwo;
}data;

struct data _dataStore[25];
int dataCount = 0;

int addData(){

    printf("\n\t\t\tPacket Source - ");
    scanf("%d", &_dataStore[dataCount].testone);

    printf("\t\t\tPacket Destination - ");
    scanf("%d", &_dataStore[dataCount].testtwo);

    system("CLS");

    return 0;
}

void listData(){

    int i = 0;

    for (i = 0; i < dataCount; i++){
        printf("data stored - %d: ",dataCount);
        printf("%d___%d \n",          _dataStore[i].testone,_dataStore[i].testtwo);
    }
 }


int main()
{

    char choice;

    do{
        printf("\t\t\t Counter - %i", dataCount+1);
        printf("\n\t\t\t1 - Add data. \n");
        printf("\t\t\t2 - List data. \n");
        printf("\n\t\t\tEnter your choice - ");

        fflush(stdin);
        choice = getchar();
        getchar();

        switch(choice){


        case '1':
            addData();
            dataCount++;
            system("CLS");
            break;


        case '2':
            system("CLS");
            listData();
            break;

        case '5':
            printf("Will exit...");
            break;

        default:
            printf("Invalid input \n");
            break;
        }
    }while (choice != '5');
    return 0;
}

声音继续在对方玩

1 个答案: